Question

A solution of copper sulfate is treated with zincmetal. How many grams of copper are produced if 2.9 g of zinc are consumed?

Answer 1

Answer:

2.8212 g

Explanation:

The reaction of copper sulfate with zinc is shown below as:

$CuSO_4+Zn\rightarrow ZnSO_4+Cu$

Given that :

Amount of zinc = 2.9 g

Molar mass of zinc = 65.38 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, molesare:

$moles= \frac{2.9\ g}{65.38\ g/mol}$

$moles= 0.0444\ mol$

From the reaction,  

1 mole of zinc on reaction forms 1 mole of copper

Thus,

0.0444 moles of zinc on reaction forms 0.0444 mole of copper

Mass of copper = moles×Molar mass

Molar mass of copper = 63.54 g/mol

Mass of copper = 0.0444 ×63.54 g = 2.8212 g