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bogdanovich [222]
3 years ago
13

Indicate the mechanistic symbol (SN1, SN2) that is most consistent with the following statement. Select the single best answer.

The substitution product obtained by the solvolysis of tert−butyl iodide in methanol arises by this mechanism
Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

The most consistent mechanism is SN1.

Explanation:

The solvolysis of tert-butyl iodide in methanol will arise by the SN1  mechanism.

The reason for that is due the geometric structure of tert-butyl. The tertiary structure allows the formation of a stable carbocation, after the loss of the iodide ion. The carbocation will then be attacked by methanol molecules forming an eter.

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Ethanol is a common laboratory solvent and has a density of 0.789 g/ml. What is the mass, in grams, of 125 ml of ethanol?
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The density of a material is its unique property by which a unknown material can be identified and also the impurity (if present) in a material can be concluded. Mathematically the density can be expressed as-\frac{mass}{volume}. Thus from the mathematical expression we can say that the density is the mass per unit volume of a material. Here the density of ethanol is given 0.789 g/mL. Thus the weight of the 1 mL ethanol is 0.789g. Thus the weight of the 125 mL of ethanol will be (125×0.789) = 98.625 g.

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<em>A conclusion that can be drawn about the movement of life to land is that;</em>

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What is the name of a hydrocarbon that has the formula CH3(CH2)4CCH?
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3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O
Ksivusya [100]

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

  • Cu: 3 moles
  • HNO₃: 8 moles
  • Cu(NO₃)₂: 3 moles
  • NO: 2 moles
  • H₂O: 4 moles

<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}

<u><em>amount of moles of NO= 6.75 moles</em></u>

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

Learn more about reaction stoichiometry:

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