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3 years ago

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Methane is a major component of natural gas, which is used as a fuel in homes. write a balanced equation for the complete oxidat

ion reaction that occurs when methane (ch4) burns in air. use the smallest possible integer coefficients.

1 answer:

Likurg_2 [28]3 years ago

8 0

CH4 +2 O2 ----> CO2 +2H2O

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What would happen if grasshoppers population increased

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Their prey would decrease

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A 603.0 g/hr stream of liquid methyl alcohol, also called methanol, (CH3OH) at 8.10 atm and 26.0°C was held at constant pressure

mafiozo [28]

Answer:

$Q=\frac{1385270 J}{hr}$

Explanation:

Methanol's molecular weight: $M=32 g/mol$

Methanol's heat of vaporization: $\Delta H_{vap}=69.69 kJ/mol$

Ideal gas heat capacity (Cp):

$Cp=\frac{5}{2}*R$ where R is the gas constant

$Cp=\frac{5}{2}*8.314 \frac{J}{mol*C}=20.78\frac{J}{mol*C}$

The heat needed to vaporize and bring the gs to 210°C is:

$Q=\frac{603 g/hr}{32 g/mol}*(69690\frac{J}{mol}+20.78\frac{J}{mol*C}*(210-26)C)$

$Q=\frac{1385270 J}{hr}$

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3 years ago

Paraphin [41]

I thinkkkk it’s OCHbl

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Click the button that shows the correct relationship of the electron affinities of the elements sodium and phosphorus.

VikaD [51]

Answer:

The second option

Explanation:

I took the quiz and got it correct

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3 years ago

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A 1.24g sample of a hydrocarbon, when completely burned in an excess of O2 yields 4.04g Co2 and 1.24g H20. Draw plausible struct

arsen [322]

Answer:

Plausible structure has been given below

Explanation:

Molar mass of $CO_{2}$ is 44 g/mol and molar mass of $H_{2}O$ is 18 g/mol
Number of mole = (mass/molar mass)

4.04 g of $CO_{2}$ = $\frac{4.04}{44}moles$ $CO_{2}$ = 0.0918 moles of $CO_{2}$

1 mol of $CO_{2}$ contains 1 mol of C atom

So, 0.0918 moles of $CO_{2}$ contains 0.0918 moles of C atom

1.24 g of $H_{2}O$ = $\frac{1.24}{18}moles$ $H_{2}O$ = 0.0689 moles of $H_{2}O$

1 mol of $H_{2}O$ contain 2 moles of H atom

So, 0.0689 moles of $H_{2}O$ contain $(2\times 0.0689)moles$ of $H_{2}O$ or 0.138 moles of $H_{2}O$

Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3

Empirical formula of hydrocarbon is $C_{2}H_{3}$

So, molecular formula of one of it's analog is $C_{4}H_{6}$

Plausible structure of $C_{4}H_{6}$ has been given below.

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3 years ago