Question

A solid, insulating sphere of radius 40.0 cm has positive charge distributed uniformly throughout its volume. The electric field at a distance of 80.0 cm from the center of the sphere is 6.00 N/C. What is the electric field at a distance of 20.0 cm from the center of the sphere (in N/C)

Answer 1

Answer:

The correct answer to the following question will be "12.0 N/C".

Explanation:

As we know,

Charged from the inside of the sphere throughout consideration of the electrical field or inside sphere.  

⇒  $E_0=\frac{KQ}{r_0^{2}}$

Now,

⇒  $Q=\frac{E_0r_0^{2}}{k}$

On putting the values in the above formula, we get

⇒      $=\frac{6.00\times 80.0}{9\times 10^9}(\frac{10^{-2}}{2})^2$

⇒      $=4.267\times 10^{-10} \ C$

Electric field within the sphere at that same distance of 20.0 cm from either the core.

⇒  $E_i=\frac{kQr_i}{R^3}$

On putting the values, we get

⇒      $=\frac{(9\times 10^9)(4.267\times 10^{-10})(20.0)}{(80.0)^3(\frac{10^{-2}}{1} )^2}$

⇒      $=12.0 \ N/C$