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ira [324]
3 years ago
8

"Using your favorite search engine and the resources of your library, develop a set of recommendations regarding the possible us

e of cloud computing services to operate the City of Asheville mobile app server. In about 200 words, outline pros and cons of this solution to Feldman’s concerns."
Engineering
1 answer:
alina1380 [7]3 years ago
5 0

Answer:

Cloud computing services are going to be very important to supporting Ashville's mobile app since it has different uses. These applications uses include; data storage, as well as helping to provide network to any business data related work. This will improve the city of Ashville's mobile app operations considerably.

The benefits of using cloud computing are; it allows a business managers to be more concerned with running the business themselves rather than maintaining the data center. The use of cloud computing allows a company's IT administrators to focus on managing the company's operations, thereby allowing performance to be enhanced of the business enterprise.

A commercial company is able to create new technologies more rapidly with the use of cloud computing. Furthermore, the enterprise will be able to automate its activities using cloud computing. Cloud computing is also very important as it is more affordable and thus promotes the company's growth in the market. Cloud computing is also enhancing the global presence of the Ashville mobile app. The drawbacks of using cloud computing include the following; due to using the cloud infrastructure, the company's performance may be unreliable. People believe that cloud computing is not reliable and that cloud computing may not be secure at last and can't always be right for all workloads.

Explanation:

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A driver is traveling at 90 km/h down a 3% grade on good, wet pavement. An accident
Paul [167]

Answer:

0.35

Explanation:

We resolve the component of the weight of the car along and perpendicular to the grade. We have mgsinФ and mgcosФ where Ф = angle of grade.

Now, the frictional force f = μN = μmgcosФ where μ = coefficient of friction

So, the net force along the grade is F = mgsinФ - μmgcosФ.

The work done by this force moving a distance, d along the grade is

W = (mgsinФ - μmgcosФ)d

This work equals the change in kinetic energy of the car. So ΔK = 1/2m(v₂² - v₁²) = W = (mgsinФ - μmgcosФ)d

1/2m(v₂² - v₁²) = (mgsinФ - μmgcosФ)d

1/2(v₂² - v₁²) = (gsinФ - μgcosФ)d

(v₂² - v₁²)/2d = (gsinФ - μgcosФ)

dividing through by gcosФ, we have

(v₂² - v₁²)/2dgcosФ = (gsinФ/gcosФ) - μgcosФ/gcosФ

(v₂² - v₁²)/2dgcosФ = tanФ -  μ

μ = tanФ - (v₂² - v₁²)/2dgcosФ

given that tanФ = 3% = 3/100 and 1 + tan²Ф = 1/cos²Ф, cosФ = 1/(√1 + tan²Ф) = 1/(√1 + (3/100)²) = 1/(√1 + (9/10000)) = 1/(√10000 + 9/10000) = 1/√(10009/10000) = 100/√10009 = 100/100.05 = 0.9995.

Also, given that v₁ = 90 km/h = 90 × 1000/3600 m/s = 25 m/s and v₂ = 45 km/h = 45 × 1000/3600 m/s = 12.5 m/s, d = 75 m and g = 9.8 m/s².

So, substituting the values of the variables into the equation, we have

μ = tanФ - (v₂² - v₁²)/2dgcosФ

μ = 3/100 - ((12.5 m/s)² - (25 m/s)²)/(2 × 75 m × 9.8 m/s² × 0.9995)

μ = 3/100 - ((156.25 m/s)² - (625 m/s)²)/1,469.265 m²/s²

μ = 3/100 - (-468.75 m²/s²)/1,469.265 m²/s²

μ = 3/100 + 468.75 m²/s²/1,469.265 m²/s²

μ = 0.03 + 0.32

μ = 0.35

So, theoretical friction  coefficient is 0.35

4 0
3 years ago
Question 64 (1 point)
Xelga [282]

Answer: c fine sand aggregate, portland cement,fine sand

Explanation:

7 0
3 years ago
5. Create a function named second_a that uses a list comprehension. The function will take a single integer parameter n. Find ev
Mekhanik [1.2K]

Answer:

//Program was implemented using C++ Programming Language

// Comments are used for explanatory purpose

#include<iostream>

using namespace std;

unsigned int second_a(unsigned int n)

{

int r,sum=0,temp;

int first;

for(int i= 1; I<=n; i++)

{

first = n;

//Check if first digit is 3

// Remove last digit from number till only one digit is left

while(first >= 10)

{

first = first / 10;

}

if(first == 3) // if first digit is 3

{

//Check if n is palindrome

temp=n; // save the value of n in a temporary Variable

while(n>0)

{

r=n%10; //getting remainder

sum=(sum*10)+r;

n=n/10;

}

if(temp==sum)

cout<<n<<" is a palindrome";

else

cout<<n<<" is not a palindrome";

}

}

}

Explanation:

The above code segments is a functional program that checks if a number that starts with digit 3 is Palindromic or not.

The program was coded using C++ programming language.

The main method of the program is omitted.

Comments were used for explanatory purpose.

8 0
2 years ago
A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the mot
Thepotemich [5.8K]

78950W the answer

Explanation:

A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor

A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor

5 0
2 years ago
- Viscoelastic stress relaxation
My name is Ann [436]

Explanation:

The correct answers to the fill in the blanks would be;

1. Viscoelastic stress relaxation refers to scenarios for which the stress applied to a polymer must decay over time in order to maintain a constant strain. Otherwise, over time, the polymer chains will slip and slide past one another in response to a constant applied load and the strain will increase (in magnitude).

2. Viscoelastic creep refers to scenarios for which a polymer will permanently flow over time in response a constant applied stress.

The polymer whose properties have been mentioned above is commonly known as Kevlar.

It is mostly used in high-strength fabrics and its properties are because of several hydrogen bonds between polymer molecules.

5 0
2 years ago
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