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3 years ago

Convert 0.025 in into mm.

Engineering

2 answers:

Leto [7]3 years ago

8 0

Answer:

.025 inch = 0.635 mm

Explanation:

We know that 1 inch = 2.54 cm

also we know that 1 cm = 10 mm

Thus 1 inch = 2.54 x 10 mm

=> 1 inch = 25.4 mm

Hence 0.025 inch = 25.4 x .025 mm

Thus .025 inch = 0.635 mm

malfutka [58]3 years ago

3 0

Answer: 0.025 in = 0.065 mm

Explanation: To convert the value in inches to mm we have to multiply the inches by the conversion factor 25.4.

So, 0.025 × 25.4 = 0.065 mm (millimeter)

Conversion formula for calculation in (inch) into mm is:

Value in mm = Value in in × 25.4

One inch is equal to the 25.4 mm.

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The current through a 10-mH inductor is 10e−t∕2 A. Find the voltage and the power at t = 8 s.

NNADVOKAT [17]

Answer:

voltage = -0.01116V

power = -0.0249W

Explanation:

The voltage v(t) across an inductor is given by;

v(t) = L $\frac{di(t)}{dt}$ -----------(i)

Where;

L = inductance of the inductor

i(t) = current through the inductor at a given time

t = time for the flow of current

From the question:

i(t) = $10e^{-t/2}$ A

L = 10mH = 10 x 10⁻³H

Substitute these values into equation (i) as follows;

v(t) = $(10*10^{-3})\frac{d(10e^{-t/2})}{dt}$

Solve the differential

v(t) = $(10*10^{-3})\frac{-1*10}{2} (e^{-t/2})$

v(t) = -0.05 $e^{-t/2}$

At t = 8s

v(t) = v(8) = -0.05 $e^{-8/2}$

v(t) = v(8) = -0.05 $e^{-4}$

v(t) = -0.05 x 0.223

v(t) = -0.01116V

(b) To get the power, we use the following relation:

p(t) = i(t) x v(t)

Power at t = 8

p(8) = i(8) x v(8)

i(8) = i(t = 8) = $10e^{-8/2}$

i(8) = $10e^{-4}$

i(8) = 10 x 0.223

i(8) = 2.23

Therefore,

p(8) = 2.23 x -0.01116

p(8) = -0.0249W

7 0

3 years ago

Read 2 more answers

Write a program that asks the user for the name of a file. The program should display the number of words that the file contains

Flura [38]

Answer:

import java.io.*;

import java.util.Scanner;

public class CountWordsInFile {

public static void main(String[] args) throws IOException {

Scanner keyboard = new Scanner(System.in);

System.out.print("Enter file name: ");

String fileName = keyboard.next();

File file = new File(fileName);

try {

Scanner scan = new Scanner(file);

int count = 0;

while(scan.hasNext()) {

scan.next();

count += 1;

}

scan.close();

System.out.println("Number of words: "+count);

} catch (FileNotFoundException e) {

System.out.println("File " + file.getName() + " not present ");

System.exit(0);

}

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3 years ago

The creation of designer drugs is outpacing the ability of society to enact laws to prohibit them. Many of these substances have

Andreas93 [3]

Answer:

The creation of "designer drugs" is outpacing the ability of society to enact laws to prohibit them. Many of these substances have negative side effects, ranging from violent behavior to death.

40. Which of the following responses to the problem would best fit the "crime control" philosophy?

a. Government takes steps to limit the availability of ingredients used in the manufacture of designer drugs.

b. Design a public awareness campaign to warn potential users of the dangers presented by use of these drugs.

c. Partner with community leaders to identify underlying social issues promoting the drug subculture.

d. Pass legislation and increase enforcement efforts to send a message of "zero tolerance" to those who manufacture, sell, and use designer drugs

The answer to the above question is

d. Pass legislation and increase enforcement efforts to send a message of "zero tolerance" to those who manufacture, sell, and use designer drugs

Explanation:

State governments, naturally provide early response to the domestic issue of designer drug abuse than the federal government through the early banning of synthetic drug use.

State legislation on restricting designer drug use can be defined into three groups including

1. Specific synthetic substance ban

2. Ban on generic language

3. Ban based on the effect a substance has on the body.

It can be clearly demonstrated that legislation which combines this three categories is highly effective in reducing the supply and use of designer drugs.

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3 years ago

Liquid flows at steady state at a rate of 2 lb/s through a pump, which operates to raise the elevation of the liquid 100 ft from

Greeley [361]

Answer:

D) 1.04 Btu/s from the liquid to the surroundings.

Explanation:

Given that:

flow rate (m) = 2 lb/s

liquid specific enthalpy at the inlet ( $h_{1}=40.09$ Btu/lb)

liquid specific enthalpy at the exit ( $h_{2}=40.94$ Btu/lb)

initial elevation ( $z_1=0ft$ )

final elevation ( $z_2=100ft$ )

acceleration due to gravity (g) = 32.174 ft/s²

$W_{cv}$ = 3 Btu/s

The energy balance equation is given as:

$Q_{cv}-W{cv}+m[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0$

Since kinetic energy effects are negligible, the equation becomes:

$Q_{cv}-W{cv}+m[(h_1-h_2)+g(z_1-z_2)]=0$

Substituting values:

$Q_{cv}-(-3)+2[(40.09-40.94)+\frac{32.174(0-100)}{778*32.174} ]=0\\Q_{cv}+3+2[-0.85-0.1285 ]=0\\Q_{cv}+3+2(-0.9785)=0\\Q_{cv}+3-1.957=0\\Q_{cv}+1.04=0\\Q_{cv}=-1.04\\$

The heat transfer rate is 1.04 Btu/s from the liquid to the surroundings.

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3 years ago

The penalty for littering 15 lb or less is _____.<br> A. $25<br> B. $50<br> C. $100<br> D. $150

Marina CMI [18]

Answer:

D the closest

Explanation:

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