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guajiro [1.7K]
2 years ago
5

Object A is 71 degrees and object B is 75 degrees how will thermal energy flow

Physics
1 answer:
Tasya [4]2 years ago
3 0

Given :

Object A is 71 degrees and object B is 75 degrees .

To Find :

How will thermal energy flow.

Solution :

We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.

So, in the given question energy will flow from object B from object A.

Hence, this is the required solution.

You might be interested in
How much current must flow through a wire to make a magnetic field as strong as Earth's field (5.00 x 10^-5 T) 1.00 m away from
torisob [31]

Answer:

250 A

Explanation:

B = 5 x 10^-5 T, r = 1 m

Let current be i.

the magnetic field due to a straight current carrying conductor is given by

B = μ0 / 4π x 2i / r

5 x 10^-5 = 10^-7 x 2 x i / 1

i = 250 A

7 0
3 years ago
A block slides along a frictionless surface with 220 J of kinetic energy. It then goes up a frictionless ramp. When the kinetic
aev [14]

Hello!

For the explanation of this energy conservation exercise, where we'll use <u>energy conservation law</u>, let's see what this principle proposes.

How you should know, mechanical energy conserves in every point, that is to say mechanical energy is same in A point like B point. (Mechanical energy will be represented by "Me")

Once time we know that, let's take the 220 Joules momentum like A point, and when 55 Joules momentum like B point.

Then, let's use the <u>energy conservation principle:</u>

Me(A) = Me(B)

  • We know Mechanical energy in A point, so just lets replace according to our data:

220 J = Me(B)

  • In B point, we know kinetic energy, but <u>we dont know gravitational potential energy</u>, so lets descompose Mechanical energy, into kinetic energy and gravitational potential energy:

220 J = Ke + Gpe

  • We know kinetic energy value, so lets replace it:

220 J = 55 J + Gpe

  • Finally, just clean Gpe and resolve it:

Gpe = 220 J - 55 J = 165 J

Gravitational potential energy is of One hundred sixty five Joules <u>(165 J).</u>

                                                                                  ║Sincerely, ChizuruChan║

8 0
2 years ago
Hi
Vera_Pavlovna [14]

1) the cotton bolls burst open, and the white cotton fiber can be seen. Ginning: The cotton picked up from the plants has seeds in it. The process of removing cotton seeds from pods is called ginning. Ginning was traditionally done by hand.

2) Preparation

To be used for thread or fabric, raw seed cotton must cleaned and free of debris. Seeds, burrs, dirt, stems and leaf material are removed from the cotton during ginning.

Module feeders break the modules apart and feed the cotton into the gin.

Some module feeders have giant conveyors moving the modules into stationary heads.

Other module feeders are self-propelled, moving down a track alongside the modules.

Once in the cotton gin, the seed cotton moves through dryers and through multiple cleaning machines that remove the gin waste such as burrs, dirt, stems and leaf material from the cotton. Once thoroughly clean and dry, the cotton goes to the gin stand where circular saws with small, sharp teeth pluck the fiber from the seed. This process makes the sliver smoother so more uniform yarns can be produced. Then the cotton is packed tightly into bales, ready to be processed into textiles.

Even though the cotton is cleaned during the ginning process, it's not nearly as clean as  it needs to be. Cotton fibers are shaved from the bales and sent through a series of cleaning and drying machines. The mixed and fluffed-up cotton goes into a carding machine which finishes the cleaning and straightening of the fibers, making them into a soft, untwisted rope called a sliver (pronounced sly-ver).

The sliver is drawn out to a thinner strand and given a slight twist to improve strength, then wound on bobbins (spools wound with the thread-like product for storage).  

It is now called roving and the roving bobbins are now ready for the spinning process.

Spinning

On modern spinning frames, yarn is mare directly from the sliver. The spinning devices take fibers from the sliver and rotate it up to 2,500 revolutions in a second twist that makes fibers into a yarn for weaving or knitting into fabrics.

Spinning is the last process in yarn manufacturing. Today's mills draw and twist the roving into yarn and place it on bobbins. They do this quite efficiently. A large, modern mill can produce enough yarn or thread in 30 days to wrap around the earth 2300 times or go to and return from the moon 235 times. With the use of automatic winding, the yarn bobbins are transferred to larger bobbins called cheese cones. These cheese cones can be stored until they are needed in the weaving process.

Weaving

Looms weave cotton yarns into fabrics the same way the first hand-weaving frames did. Modern looms work at great speeds, interlacing the length-wise yarns (warp) and the crosswise yarns (weft).

Warp refers to yarns that run lengthwise in woven goods. In preparation of warp yarns for weaving, hundreds of yarn strands are wound from cheese cones onto a large warp beam. Yarns on this beam are then coated with a starch mixture (sizing compound) to add strength for weaving.

Weft is the yarn that runs crosswise in woven goods and may be referred to as filling yarn. Sizing is not placed on weft because flexibility is needed in the weaving process.

In today's most modern mills, the weft is fed into the loom from cheese cones with air-jets at such a high speed that its movement cannot be seen.

The woven fabric, called gray goods, is sent to a finishing plant where it is bleached, pre-shrunk, dyed, printed and given a special finish before being made into clothing or products for the home. Other machines make knits for use in shirts, sweaters or blankets.

this website will help you: https://www.quilting-in-america.com/process-of-making-cotton.html

i hope this helps :)

6 0
3 years ago
a 1150 kg car is on a 8.70 hill. using x-y axis tilted down the plane, what is the x-component of the normal force(unit=N)
rodikova [14]

The x-component of the normal force is equal to <u>1706.45 N.</u>

Why?

To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:

N_{x}=W*Sin(\alpha)=mg*Sin(\alpha)\\\\N_{y}=W*Cos(\alpha)=mg*Cos(\alpha)

Now, using the given information, we have:

mass=m=1150Kg\\\alpha=8.70\°\\g=9.81\frac{m}{s^{2}}

Calculating, we have:

N_{x}=mg*Sin(\alpha)

N_{x}=1150Kg*9.81\frac{m}{s^{2}}*Sin(8.70\°)\\\\N_{x}=11281.5\frac{Kg.m}{s^{2} }*Sin(8.70\°)=1706.45\frac{Kg.m}{s^{2} }=1706.45.23N

Hence, we have that the x-component of the normal force is equal to  <u>1706.45 N.</u>

Have a nice day!

3 0
3 years ago
A constant torque of 200Nm turns a wheel about its centre. The moment of inertia of it about the axis is 100kgm^s . Find the kin
AleksAgata [21]
It would turn  160 degrees after twenty truns

<span />
3 0
3 years ago
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