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Kryger [21]
3 years ago
7

When a car is on an inclined bank of angle θ and rounding a curve with no friction, what is the centripetal force equal to? a. T

he weight of the car b. N cos (θ) c. N sin (θ) d. Zero

Physics
1 answer:
k0ka [10]3 years ago
5 0

Answer:

F_{net}=N\ sin\theta

Explanation:

Let a car of m is on an incline bank of angle θ and it is rounding a curve with no friction. We need to find the centripetal force acting on it.    

The attached free body diagram shows the car on the banked turn. It is clear that,

In vertical direction,

N\ cos\theta=mg

In horizontal direction,

F_{net}=F_{centripetal}

F_{net}=N\ sin\theta

So, the centripetal force is equal to N\ sin\theta. Hence, the correct option is (c).

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Answer:581.87 K

Explanation:

Given

Sphere is melted to form a square

Let the radius of sphere be r and square has a side a

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\frac{4\pi}{3}r^3=a^3

Surface area of sphere A_s=4\pi r^2

Surface area of cube A_c=6a^2

Total emmisive remains same

Thus P=A\epsilon \sigma T^4

A_sT_s^4=A_cT_c^4

\frac{T_c^4}{T_s^4}=\frac{A_s}{A_c}

\frac{T_c^4}{T_s^4}=\frac{1}{2}\times \left ( \frac{4\pi}{3}\right )^{\frac{1}{3}}

\frac{T_c}{T_s}=\frac{1}{2^{0.25}}\times \left ( \frac{4\pi}{3}\right )^{\frac{1}{12}}

T_c=T_s\times \frac{1}{2^{0.25}}\times \left ( \frac{4\pi}{3}\right )^{\frac{1}{12}}

T_c=614\times \frac{1.12679}{1.189}

T_c=581.87 K

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3 years ago
A driver brings a car to a full stop in 2.0 s. If the car was
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sammy [17]

Answer:

B. 3.45 x 10^3

Explanation:

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3 years ago
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AleksAgata [21]

Answer:

6.39 J of energy is needed to generate 0.71 * 10⁻¹⁶ kg mass

Explanation:

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The amount of energy needed to generate a mass of 0.71 * 10⁻¹⁶ kg is calculated as follows:

E = (0.71 * 10⁻¹⁶) (3 * 10⁸)²

E = 0.71 * 10⁻¹⁶ * 9 * 10¹⁶

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