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NemiM [27]
3 years ago
5

102) Consider massive gliders that slide friction- free along a horizontal air track Glider A has a mass of 1 kg, aspeed of 1 m/

s, and collides with Glider B that has a mass of 5 kg and is at rest. If they stick upon collision, theirspeed after collision will beA) lm/s.B) 1/6 m/s.C) 1/5 m/s.D) 1/4 m/s.E) none of these.
Physics
1 answer:
Darya [45]3 years ago
3 0

Answer:

B. 1/6 m/s

Explanation:

Parameters given:

Mass of first glider, m = 1 kg

Initial speed of first glider, u = 1 m/s

Mass of second glider, M = 5 kg

Initial speed of second glider, U = 0 m/s.

Using the principle of conservation of momentum, we have that:

Total initial momentum = Total final momentum

=> m*u + M*U = m*v + M*V

Where v is the final velocity of the first glider and V is the final velocity of the second glider.

Since they stick upon collision, their final velocities are the same, hence, v = V

m*u + M*U = m*v + M*v

m*u + M*U = (m + M)*v

Also, since the second glider is initially at rest, U = 0

m*u = (m + M)*v

Therefore,

v = (m*u) / (m + M)

v = (1 * 1) / (1 + 5)

v = 1/6 m/s

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Answer:

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Explanation

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3 years ago
If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed
beks73 [17]

Answer:

v = 5.9 x 10⁷ m/s

Explanation:

The kinetic energy of the electron in terms of potential difference is given as:

K.E = eV--------------- equation (1)

where,

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V = Potential Difference = 9.9 KV = 9900 Volts

The kinetic energy in general is given as:

K.E = \frac{1}{2}mv^{2}\\--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

\\\frac{1}{2}mv^{2} = eV\\\\\frac{1}{2}(9.1\ x\ 10^{-31}\ kg)v^{2} = (1.6\ x\ 10^{-19}\ C)(9900\ volts)\\\\v = \sqrt{34.81\ x\ 10^{14}} \\

<u>v = 5.9 x 10⁷ m/s</u>

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How does a helicopter fly ? ( I need it explained in the view of physics)
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because blades of helicopter create a high pressure difference between lower and higher portion of blade so due to this pressure difference helicopter became able to fly.

Explanation:

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Two objects have a force of gravity of 100 N. If the distance between both objects decreases by a factor of 7, while the masses
Shkiper50 [21]

The gravitational force <em>F</em> between two masses <em>M</em> and <em>m</em> a distance <em>r</em> apart is

<em>F</em> = <em>G M m</em> / <em>r</em> ²

Decrease the distance by a factor of 7 by replacing <em>r</em> with <em>r</em> / 7, and decrease both masses by a factor of 8 by replacing <em>M</em> and <em>m</em> with <em>M</em> / 8 and <em>m</em> / 8, respectively. Then the new force <em>F*</em> is

<em>F*</em> = <em>G </em>(<em>M</em> / 8) (<em>m</em> / 8) / (<em>r</em> / 7)²

<em>F*</em> = (1/64 × <em>G M m</em>) / (1/49 × <em>r</em> ²)

<em>F*</em> = 49/64 × <em>G M m</em> / <em>r</em> ²

In other words, the new force is scaled down by a factor of 49/64 ≈ 0.7656, so the new force has magnitude approx. 76.56 N.

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