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3 years ago

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102) Consider massive gliders that slide friction- free along a horizontal air track Glider A has a mass of 1 kg, aspeed of 1 m/

s, and collides with Glider B that has a mass of 5 kg and is at rest. If they stick upon collision, theirspeed after collision will beA) lm/s.B) 1/6 m/s.C) 1/5 m/s.D) 1/4 m/s.E) none of these.

1 answer:

Darya [45]3 years ago

3 0

Answer:

B. 1/6 m/s

Explanation:

Parameters given:

Mass of first glider, m = 1 kg

Initial speed of first glider, u = 1 m/s

Mass of second glider, M = 5 kg

Initial speed of second glider, U = 0 m/s.

Using the principle of conservation of momentum, we have that:

Total initial momentum = Total final momentum

=> m*u + M*U = m*v + M*V

Where v is the final velocity of the first glider and V is the final velocity of the second glider.

Since they stick upon collision, their final velocities are the same, hence, v = V

m*u + M*U = m*v + M*v

m*u + M*U = (m + M)*v

Also, since the second glider is initially at rest, U = 0

m*u = (m + M)*v

Therefore,

v = (m*u) / (m + M)

v = (1 * 1) / (1 + 5)

v = 1/6 m/s

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Answer:

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Answer:

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Given that the amount of material is constant in the process:

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In an isobaric process the pressure is constant so:

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$\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }$

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Replacing on the ideal gases formula the pressure at this piont is:

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$P_{2} V_{2} = P_{3} V_{3}$

$P_{3} = \frac{P_{2} V_{2}}{V_{3}}$

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