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NemiM [27]
3 years ago
5

102) Consider massive gliders that slide friction- free along a horizontal air track Glider A has a mass of 1 kg, aspeed of 1 m/

s, and collides with Glider B that has a mass of 5 kg and is at rest. If they stick upon collision, theirspeed after collision will beA) lm/s.B) 1/6 m/s.C) 1/5 m/s.D) 1/4 m/s.E) none of these.
Physics
1 answer:
Darya [45]3 years ago
3 0

Answer:

B. 1/6 m/s

Explanation:

Parameters given:

Mass of first glider, m = 1 kg

Initial speed of first glider, u = 1 m/s

Mass of second glider, M = 5 kg

Initial speed of second glider, U = 0 m/s.

Using the principle of conservation of momentum, we have that:

Total initial momentum = Total final momentum

=> m*u + M*U = m*v + M*V

Where v is the final velocity of the first glider and V is the final velocity of the second glider.

Since they stick upon collision, their final velocities are the same, hence, v = V

m*u + M*U = m*v + M*v

m*u + M*U = (m + M)*v

Also, since the second glider is initially at rest, U = 0

m*u = (m + M)*v

Therefore,

v = (m*u) / (m + M)

v = (1 * 1) / (1 + 5)

v = 1/6 m/s

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Two identical stones, A and B, are thrown from a cliff from the same height and with the same initial speed. Stone A is thrown v
Taya2010 [7]

Answer:

Option A

Explanation:

This can be explained based on the conservation of energy.

The total mechanical energy of the system remain constant in the absence of any external force. Also, the total mechanical energy of the system is the sum of the potential energy and the kinetic energy associated with the system.

In case of two stones thrown from a cliff one vertically downwards the other vertically upwards, the overall gravitational potential energy remain same for the two stones as the displacement of the stones is same.

Therefore the kinetic energy and hence the speed of the two stones should also be same in order for the mechanical energy to remain conserved.

5 0
3 years ago
Read 2 more answers
In a 30.0-s interval, 500 hailstones strike a glass window with an area of 0.600m2 at an angle of 45.0°to the window surface. Ea
aliina [53]

or one hailstone we have;
Force = Mass X acceleration = 0.005kg x 9.8.} This is when the hailstone is not inclined at an angle.
When the hailstone is inclined at an angle of 45, then the component of force along the glass window will be F =0.005kg x 9.8 x sin45= 0.005kg x 9.8 x 0.707= 0.0346N.
Therefore, total force for the 500 hailstones would be 500x0.0346N=17.32N
This force is acting on an area equal to 0.600m2
Pressure = Force per unit area = 17.32N/0.600m2 = 28.9Pa

5 0
3 years ago
A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler
Pepsi [2]

Answer:

331665750000\ m/s^2

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = 1.989\times 10^{30}\ kg

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2

The gravitational acceleration at the surface of such a star is 331665750000\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s

The velocity of the object would be 3257806.62409 m/s

8 0
3 years ago
A car with mass 450 kg has a kinetic energy of 16,256 j. What is the speed of the car?
Vikentia [17]
Do you still need the answer ?
7 0
3 years ago
When a fluid flows over an object, the "friction drag": __________.A.is the drag due to the shear stress only. B. depends only o
astra-53 [7]

Answer:

D. is greater for turbulent flow than for laminar flow

Explanation:

what is friction drag?

  • friction drag is a phenomenon experienced when a body moves through a fluid. A practical example can be seen in the mild warmth we experience rubbing the palm's of one's hand together only in this case we are dealing with a solid body and a fluid (e.g air, water). friction drag is directly proportional to the area of the surface in contact with the fluid and increases as velocity increases. We see a practical example of this when the rate at which one rubs the palms together is fast but we use the word turbulent when we are dealing with fluids. Turbulent flow creates more friction drag than laminar flow( Flow between a smooth body and fluid) due to its greater interaction with the surface of the body
  • it is important to know that friction is also called viscous drag or skin drag
  • I recommend Richardson and coulson vol 2 textbook, page 149, Chemical enginering fluid mechanics textbook by Ron dardy, page 341 for clearer explanation
4 0
3 years ago
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