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Roman55 [17]
3 years ago
5

A particular planet has a moment of inertia of 8.26 × 1036 kg⋅m2 and a mass of 6.54 × 1022 kg. Based on these values, what is th

e planet's radius? Hint: Because planets are the shape of a sphere, the moment of inertia is I = (2/5)mr2.
7.12 × 106 m
1.78 × 107 m
5.05 × 1013 m
3.16 × 1014
Physics
1 answer:
SVEN [57.7K]3 years ago
3 0

Answer: Correct answer is B = 1.776933×10^{7}

Explanation:

Given :

Moment of inertia I = 8.26×10^{36} kgm^{2}

Mass of planet m = 6.54×10^{22} kg

Also, Planet is solid sphere so that, Moment of inertia is I = \frac{2}{5} mR^{2} =0.4mR^{2}

Where R is radius of planet

Putting into calculation

We get,

I = \frac{2}{5} mR^{2}

8.26×10^{36} =  0.4×6.54×10^{22}×R^{2}

8.26×10^{14} = 2.616 R^{2}

3.15749235×10^{14} = R^{2}

R =  1.776933×10^{7}

Thus, Correct answer is B = 1.776933×10^{7}

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(

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×

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