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3 years ago

Why does dry ice scream when pushed onto metal?

Chemistry

2 answers:

alisha [4.7K]3 years ago

7 0

Answer:

i thought you said dry ice cream

Shtirlitz [24]3 years ago

5 0

Because metals are good conductors they can transfer ambient heat to the surface of the dry ice.

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The amount of heat absorbed when 5.5g of aluminum is heated from 25.0c to 95.0c the specific heat of aluminum is 0.897J/(gc)

NemiM [27]

Answer:

Q=21.99 kJ

Explanation:

4 0

3 years ago

The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc

jek_recluse [69]

Answer: $K_{sp}=1.25\times 10^{-14}$

$pK_{sp}=13.90$

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as $K_{sp}$

The equation for the ionization of magnesium phosphate is given as:

$Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}$

When the solubility of $Mg_3(PO_4)_2$ is S moles/liter, then the solubility of $Mg^{2+}$ will be 3S moles\liter and solubility of $PO_4^{3-}$ will be 2S moles/liter.

Thus S = 0.173 g/L or $\frac{0.173g/L}{262.8g/mol}=0.00065mol/L$

$K_{sp}=(3S)^3\times (2S)^2$

$K_{sp}=108S^5$

$K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}$

$pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90$

5 0

3 years ago

Do bases react with metals the same way that acids do?.

mina [271]

Answer:

Bases do not react with metals in the way that acids do

Explanation:

hope this helps

pls mark brainliest

6 0

1 year ago

Which is more polar: carbon disulfide or sulfur difluoride

Ilya [14]

<span>Carbon disulfide. hope that helped</span>

4 0

3 years ago

Your apple juice has a molarity of 3.4 M and a volume of 0.895 litres. What does a student have to do to decrease the molarity t

Jlenok [28]

Answer:

4.285 L of water must be added.

Explanation:

Hello there!

In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:

$M_1V_1=M_2V_2\\\\V_2=\frac{M_1V_1}{M_2}$

Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:

$V_2=\frac{3.4M*0.895 L}{0.587M}\\\\V_2=5.18L$

It means we need to add:

$V_{H_2O} ^{added}=5.18L-0.895L=4.285L$

Of diluent water.

Regards!

6 0

2 years ago