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STALIN [3.7K]
3 years ago
3

A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol

ution thus formed? (4 points) Group of answer choices
Chemistry
1 answer:
V125BC [204]3 years ago
4 0

Answer:

The answer to your question is 0.918 l or 918 ml

Explanation:

Data

[Ca(OH)₂] = 0.530 M

mass of Ca(OH)₂ = 36 g

volume = ?

Process

To solve this problem use the formula of Molarity.

Molarity = mass of Ca(OH)₂ / volume

-Solve for Volume

Volume = moles of Ca(OH)₂ / Molarity

-Calculate the moles of Ca(OH)₂

Ca(OH)₂ = 40 + 32 + 2 = 74 g

                 74 g of Ca(OH)₂ --------------- 1 mol

                  36 g of Ca(OH)₂ --------------  x

                       x = (36 x 1) / 74

                       x = 0.486 moles

-Substitution

Volume = 0.486 / 0.530

-Result = 0.918 l or 918 ml

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