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Viktor [21]
3 years ago
11

What mass of butane in grams is necessary to produce 1.5×103 kJ1.5×103 kJ of heat? What mass of CO2CO2 is produced? Assume the r

eaction to be as follows: C4H10(g)+132O2(g)→4CO2(g)+5H2O(g),ΔHrxn=−2658 kJ
Chemistry
1 answer:
saul85 [17]3 years ago
7 0

32.8 g of Butane is required and 99.3 g of CO₂ is produced

<u>Explanation:</u>

The above mentioned reaction can be written as,

C₄H₁₀(g) + 13 O₂(g) → 4CO₂(g) + 5 H₂O(g)     where ΔH (rxn)= -2658 kJ

It is given that 1.5 × 10³ kJ of energy is produced, the original reaction says that 2658 kJ of heat is produced, which means that less than one mole of butane is used in the reaction.

That is

$\frac{1500}{2658}=0.564 \text { moles }    of butane reacted

Now this moles is converted into mass by multiplying it with its molar mass  = 0.564 mol × 58.122 g / mol

                     = 32.8 g of butane.

Mass of CO₂ produced = 0.564 ×44.01 g /mol × 4 mol

                                        = 99.3 g of CO₂

Thus 32.8 g of Butane is required and 99.3 g of CO₂ is produced

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Explanation:

Physical changes only change the appearance of a substance, not its chemical composition.

Chemical changes cause a substance to change into an entirely substance with a new chemical formula.

Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the end results are called products

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A solution contains 90 milliequivalents of HC1 in 450ml. What is its normality?
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Answer:

Normality N = 0.2 N

Explanation:

Normality is the number of gram of equivalent of solute divided of volume of solution, where the number of gram of equivalent of solute is weight of the solute divided by the equivalent weight.

Normality is represented by N.

Mathematically, we have :

\mathbf{Normality \ N = \dfrac{Number \ of \ gram \of \ equivalent\  of\  solute }{volume \ of \ solution}}

Given that:

number of gram of equivalent of solute = 90 milliequivalents 90 × 10⁻³ equivalent

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\mathbf{Normality \ N = \dfrac{90 \times 10^{-3}}{450 \times 10^{-3}}}

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Explanation:

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Consider the reaction: NO2(g) + CO(g) ⇌ NO(g) + CO2(g) Kc = 0.30 at some temperature. If the initial mixture has the concentrati
Stolb23 [73]

This is an incomplete question, here is a complete question.

Consider the reaction: NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)

Kc = 0.30 at some temperature.

If the initial mixture has the concentrations below, the system is_______.

Chemicals   Concentration (mol/L)

- NO₂            0.024

- CO               0.360

- NO               0.180

- CO₂             0.120

Possible answers:

1) not at equilibrium and will remain in an unequilibrated state.

2) not at equilibrium and will shift to the left to achieve an equilibrium state.

3) not at equilibrium and will shift to the right to achieve an equilibrium state.

4) at equilibrium

Answer : The correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

Explanation:

Reaction quotient (Qc) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

First we have to determine the value of reaction quotient (Qc).

The given balanced chemical reaction is,

NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)

The expression for reaction quotient will be :

Q_c=\frac{[NO][CO_2]}{[NO_2][CO]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q_c=\frac{(0.180)\times (0.120)}{(0.024)\times (0.360)}=2.5

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K that means product = reactant. So, the reaction is in equilibrium.

The given equilibrium constant value is, K_c=0.30

From the above we conclude that, the Q>K that means reactant < product. So, the reaction is reactant favored that means reaction must shift to the reactant or left to be in equilibrium.

Hence, the correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

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