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s344n2d4d5 [400]
3 years ago
5

how many minutes does it take light from the sun to reach earth the distance from the sun to earth is 93 million mi the speed of

light = 3.00x 10^8 m/s
Chemistry
1 answer:
Tems11 [23]3 years ago
8 0
Look to be honest, I don't know how to work out the problem, but my teacher, and my says it takes 8 minutes for the Sun's light to reach

hope my answer works :)
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Explanation:

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3 years ago
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Warm Up: Compete this conversion. Put just the number below *
Gwar [14]

Answer:

4 1/2

Explanation:

Use a ratio to find your answer

 4          6

-----  =  -------

 3           x

Cross multiply to solve for x.

4x = 18

x = 18/4

x = 4 2/4  which is the same as 4 1/2

5 0
2 years ago
The naturally occurring radioactive decay series that begins with 23592U stops with formation of the stable 20782Pb nucleus. The
dsp73

Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.

In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .

_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+X_2^4\alpha+Y_{-1}^0e

Thus for mass number : 235 = 207+4X

4X= 28

X = 7

Thus for atomic number : 92 = 82+2X-Y

2X- Y = 10

2(7) - Y= 10

14-10 = Y

Y= 4

_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+7_2^4\alpha+4_{-1}^0e

Thus there are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

3 0
3 years ago
What is the molar concentration of a solution prepared by dissolving 8.63 g of Ba(NO3)2 (molar mass = 261.35 g/mol) to a total v
PilotLPTM [1.2K]

Answer:

我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈

Explanation:

我實際上不知道我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈

7 0
3 years ago
Can some one help me with this soon as possible please will give brainliest
lana66690 [7]

1. C

2. C

3. In elastic deformation, the deformed body returns to its original shape and size after the stresses are gone. In ductile deformation, there is a permanent change in the shape and size but no fracturing occurs. In brittle deformation, the body fractures after the strength is above the limit. 

4. Normal faults are faults where the hanging wall moves in a downward force based on the footwall; they are formed from tensional stresses and the stretching of the crust. Reverse faults are the opposite and the hanging wall moves in an upward force based on the footwall; they are formed by compressional stresses and the contraction of the crust.  Thrust faults are low-angle reverse faults where the hanging wall moves in an upward force based on the footwall; they are formed in the same way as reverse faults. Last, Strike-slip faults are faults where the movement is parallel to the crust of the fault; they are caused by an immense shear stress. 


I hope this helped :D

7 0
3 years ago
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