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Luden [163]
3 years ago
11

. How much energy is lost by a 30.0g sample of water that decreases in temperature from 56.7C to 25.0C?

Chemistry
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

Q = -3980.9 j

Explanation:

Given data:

Mass of sample = 30 g

Initial temperature = 56.7 °C

Final temperature = 25 °C

Specific heat of water = 4.186 j/g.°C

Amount of heat released = ?

Formula:

Q = m.c.ΔT

Q = heat released

m = mass of sample

c = specific heat of given sample

ΔT = change in temperature

Solution:

ΔT = T2 -T1

ΔT = 25 °C - 56.7 °C = - 31.7°C

Q = m.c.ΔT

Q = 30 g × 4.186 j/g.°C ×  - 31.7°C

Q = -3980.9 j

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Volume of the box which is a cuboid can be calculated by multiplying the length, breadth and height of the given box.

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