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melomori [17]
3 years ago
13

What is happening in the picture?

Physics
2 answers:
Mariana [72]3 years ago
6 0
The boat got a hole in it and the weight of the boat and the water together sank it caused by gravity.
Veseljchak [2.6K]3 years ago
3 0
The gravity is pushing rhe boat down
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An airplane cabin is pressurized to 570 mmhg. what is the pressure inside the cabin in atmospheres?
abruzzese [7]
1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
1 atm: 760 mmHg = x: 570 mmHg
and from this, we find
x= \frac{1 atm \cdot 570 mmHg}{760 mmHg} =0.75 atm
8 0
3 years ago
Read 2 more answers
Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t
alexandr1967 [171]

Answer:

a) the one with a lower orbit    b) the one with a higher  orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

\frac{v^2}{r} = \frac{GM}{r^2}.

so the velocity is

v = \sqrt{\frac{GM}{r} }

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

T = 2\pi \sqrt{\frac{a^3}{GM} }

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0
3 years ago
A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 n frictional force. he pushes in a dire
alexandr1967 [171]

Work is calculated as the product of Force, Distance, and angular motion. In this case, the work done by gravity is perpendicular to the motion of the cart, so θ = 90°

 and W=Fdcosθ

W=35.0 N x 20.0 m x cos90

W=0 J

This means that work done perpendicular to the direction of the motion is always zero.

5 0
3 years ago
A 62 pound box is on an incline. Determine the minimum force P that would result in the box starting to slide up the incline. (i
Anon25 [30]

Answer:

F > W * sin(α)

Explanation:

The force needed for the box to start sliding up depends on the incline (α).

The external forces acting on the box would be the weight, the normal reaction and the lifting force that is applied to make it slide up.

These forces can be decomposed on their normal and tangential (to the slide plane) components.

The weight will be split into

Wn = W * cos(α) (in normal direction)

Wt = W * sin(α) (in tangential direction)

The normal reaction will be alligned with the normal axis, and will be equal to -Wn

N = -W* cos(α) (in normal direction)

To mke the box slide up, a force must be applied, that is opposite to the tangential component of the weight and at least a little larger

F > |-W * sin(α)| (in tangential direction)

8 0
3 years ago
In a collision, a car of mass 1000kg travelling at 24m/s comes to rest in 1.2s calculate
kompoz [17]

Answer:

a. 24,000

b. -20,000 N

Explanation:

a. p = m•v

1,000•24 = 24,000

1,000•0 = 0

∆p = 24,000

b. F = m•a

a = ∆v/∆t

a = -24/1.2

a = -20 m/s²

F = 1,000•(-20)

F = -20,000

8 0
3 years ago
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