Answer: a particle smaller than an atom
Explanation:
Answer: B=1.92nT
Explanation:This question uses the Biot-Savart law: the law is an equation that describes the magnetic field created by a current-carrying wire, and allows you to calculate its strength at various points.
B=(μ0/4*π)*q*v*r(unit vector)/r²
Also:
B=(μ0/4*π)*q*v*sin(θ)/r²
Where;
μ0 =permeability of free space = 4πx10-7 Hm-1
B = magnetic field in Tesla
V= velocity
r= radius
Therefore:
B=(4πx10-7/4*π)*q*v*sin(θ)/r^2
B=1x10-7*q*v*sin(θ)/r^2
Using:
q=15x10-3C
v=40m/s
tan(θ)=5/2 so θ=68.2°
r²=5²+2² (Pythagoras Theorem)
B can be calculated as:
B=1x10-7*15x10-3*40*sin(68.2)/(5²+2²)
B=1.92nT
(a) The voltage that is produced in the secondary circuit is 1,800 V.
(b) The current that flows in the secondary circuit is 1 A.
<h3>Voltage in the secondary coil</h3>
Np/Ns = Vp/Vs
where;
- Np is number of turns in primary coil
- Ns is number of turns in secondary coil
- Vp is voltage in primary coil
- Vs is voltage in secondary coil
100/1500 = 120/Vs
Vs = (120 x 1500)/100
Vs = 1,800 V
<h3>Current in the secondary coil</h3>
Is/Ip = Vp/Vs
where;
- Is is secondary current
- Ip is primary current
Is = (IpVp)/Vs
Is = (15 x 120)/1800
Is = 1 A
Thus, the voltage that is produced in the secondary circuit is 1,800 V.
Learn more about voltage here: brainly.com/question/14883923
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