<span>x = 129.9 m
y = 30.9 m
First, let's calculate the horizontal and vertical velocities involved
h = 50.0cos(30) = 43.30127 m/s
v = 50.0sin(30) = 25 m/s
The horizontal distance is simply the horizontal velocity multiplied by the time, so
43.30127 m/s * 3 s = 129.9 m
So the horizontal distance traveled is 129.9 m, so x = 129.9 m
The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get
d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2
d = 75 m - 4.9 m/s^2 * 9 s^2
d = 75 m - 44.1 m
d = 30.9 m
So the vertical distance traveled is 30.9 m, so y = 30.9 m</span>
Answer:
Explanation:
Voltage, V = 12 V
Charge, q = 2 micro coulomb = 2 x 10^-6 C
Work = energy
W = 0.5 x q x V
W = 0.5 x 2 x 10^-6 x 12
W = 12 x 10^-6 J
light energy
<span>Energy in the form of electromagnetic radiation. Most often associated with a wavelength that is visible to the eye.</span>
Answer:
t = 2.26 x 10⁵ s
Explanation:
The energy supplied to the water will be equal to the heat required for the boiling of water:
E = ΔQ
Pt = mL
where,
P = Power = 10 W
t = time = ?
m = mass of water = 1 kg
L = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg
Therefore,
![(10\ W)t = (1\ kg)(2.26\ x\ 10^6\ J/kg)\\\\t = \frac{2.26\ x\ 10^6\ J}{10\ W}\\\\](https://tex.z-dn.net/?f=%2810%5C%20W%29t%20%3D%20%281%5C%20kg%29%282.26%5C%20x%5C%2010%5E6%5C%20J%2Fkg%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B2.26%5C%20x%5C%2010%5E6%5C%20J%7D%7B10%5C%20W%7D%5C%5C%5C%5C)
<u>t = 2.26 x 10⁵ s</u>
This time will be less than the actual time taken due to some heat loss during the transmission of this heat energy to the container in which water is held.
Because gravity pictures and post the person to the force of the front or the back of the vehicle and the car has been hit from