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Pavel [41]
3 years ago
9

I need this ASAP i will give brainliest :)

Chemistry
1 answer:
shutvik [7]3 years ago
5 0

Answer:

I really dont know i just guessed :(

Explanation:

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Neptunium-237 was the first isotope of a transuranium element to be discovered. the decay constant is /s. what is the half-life
kari74 [83]

The half-life in years of Neptunium-237 which was the first isotope is 2.1 10^{6} years.

Neptunium is most stable and Neptunium-237 is undergoes alpha decay, it means Neptunium-237 is decays by the emission of alpha particles . Seven alpha particles is emitted during decay of  Neptunium-237.  Neptunium-237 is radioactive actinide  elements and first  transuranium element.

The transuranium synthesis process involves creating a transuranium element through the transmutation process . The transmutation process  is the process of creating heavy elements from light elements. Hence the process is the transmutation of light elements. There are two types: artificial and natural transmutation.

to learn more about transuranium element.

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6 0
2 years ago
Calculate the amount of solute needed for 1000 ml of 15% sodium thiosulfate
maksim [4K]
15% =  15 grams of solute in 100 mL solution

15 g --------------- 100 mL
?? ------------------ 1000 mL

1000 x 15 / 100 = 

15000 / 100 => 150 g of solute

hope this helps!
7 0
3 years ago
If a piece of matter changes shape, how does its mass change?
kap26 [50]

The law of conservation of mass states that matter cannot be created nor destroyed the answer would be D. It remains the same
5 0
3 years ago
(07.06 mc)
Slav-nsk [51]

Distilled water and sealed container are in equilibrium when these objects do not exchange more heat.

<h3>What is thermal equilibrium?</h3>

The expression 'thermal equilibrium' makes references to the phenomenon by which two objects interact with each other to exchange heat energy.

Objects in contact can transfer heat to reach a thermal equilibrium state where the temperature is the same for both objects.

In conclusion, distilled water and sealed container are in equilibrium when these objects do not exchange more heat.

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5 0
2 years ago
Determine the heat of reaction (ΔHrxn) for the combustion of ethanol (C2H5OH) by using heat of formation data: C2H5OH (l) + 3 O2
egoroff_w [7]

Answer:

\Delta H_{rxn}=-1234.782kJ

Explanation:

\Delta H_{rxn}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]

Where n_{i} and n_{j} are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

\Delta H_{f}^{0} is standard heat of formation.

So, \Delta H_{rxn}=[2mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[3mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{2}H_{5}OH)_{l}]-[3mol\times \Delta H_{f}^{0}(O_{2})_{g}]

or, \Delta H_{rxn}=[2mol\times -393.509kJ/mol]+[3mol\times -241.818kJ/mol]-[1mol\times -277.69kJ/mol]-[3mol\times 0kJ/mol]

or, \Delta H_{rxn}=-1234.782kJ

4 0
3 years ago
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