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Wewaii [24]
3 years ago
11

A solid steel sphere of density 7.86 g/cm3 and mass 1 kg spin on an axis through its center with a period of 2.3 s. given vspher

e = 4 3 π r3 , what is its angular momentum? answer in units of kg m2 /s.
Physics
1 answer:
Alenkasestr [34]3 years ago
4 0

<span>The solution for this problem is:</span>

density = mass / volume <span>
7860 = 1 / ((4/3) pi r^3) 
r^3 = 1 / (7860 * 4/3*pi) 
r = (1 / (7860 * 4/3*pi))^(1/3)</span>

= 0.067 m <span>

Inertia = (2/5)mr^2</span>

= (2/5) x 1 x 0.067^2

= 0.0017956 kg-m^2 <span>

1/2.3 = 0.4348 rev/s 

0.4348 x 2pi = 2.732 rad/s 

Angular momentum = Inertia x rad/s 

0.0017956 x 2.732 = 0.00490557 kg m^2/s</span>

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A baseball is thrown directly upward from ground level with a velocity of +15 m/s. What are the two times when the ball is 10 m
erastovalidia [21]

Answer:

time is 0.5660 s

and time is - 3.62431  s

Explanation:

velocity u = 15 m/s

height s = 10 m

acceleration due to gravity g =  –9.8 m/s²

to find out

time

solution

we will apply here distance equation that is

s = ut - 1/2× gt²   ...........1

here put all these value and get time t

here s is height and g is -9.8

so

s = ut - 1/2× gt²

10 = 15t - 1/2× (-9.8)t²

10 = 15t + 4.9t²

solve it we get t

t = 0.56630 and -3.62431

so time is 0.5660 s

and time is - 3.62431  s

8 0
4 years ago
The headwater of three different river systems are also found in Wyoming. Identify these three river systems.
S_A_V [24]

Answer:

The Wind Missouri-Mississippi, The Snake Columbia, and the Green-Colorado drainage.

Explanation:

  • The wind river ranges of the Wyoming is a major headwaters system of the united states and the rage is home to about 63 glaciers and ten of the largest glacier of the united states are found in this region. The wind river range is about 77% of the area s located in the drainage.
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5 0
3 years ago
4.5 cm3 of water is boiled at atmospheric pressure to become 4048.3 cm3 of steam, also at atmospheric pressure. Calculate the wo
Mrrafil [7]

1. 408.4 J

The work done by a gas is given by:

W=p\Delta V

where

p is the gas pressure

\Delta V is the change in volume of the gas

In this problem,

p=1.01\cdot 10^5 Pa (atmospheric pressure)

\Delta V=4048.3 cm^3 - 4.5 cm^3 =4043.8 cm^3 = 4043.8 \cdot 10^{-6}m^3 is the change in volume

So, the work done is

W=(1.01\cdot 10^5 Pa)(4043.8 \cdot 10^{-6}m^3)=408.4 J

2. 10170 J

The amount of heat added to the water to completely boil it is equal to the latent heat of vaporization:

Q = m \lambda_v

where

m is the mass of the water

\lambda_v = 2.26\cdot 10^6 J/kg is the specific latent heat of vaporization

The initial volume of water is

V_i = 4.5 cm^3 = 4.5\cdot 10^{-6}m^3

and the water density is

\rho = 1000 kg/m^3

So the water mass is

m=\rho V_i = (1000 kg/m^3)(4.5\cdot 10^{-6}m^3)=4.5\cdot 10^{-3}kg

So, the amount of heat added to the water is

Q=(4.5\cdot 10^{-3}kg)(2.26\cdot 10^6 J/kg)=10,170 J

8 0
4 years ago
Help please i need it asap
mojhsa [17]

Answer:

B

Explanation:

B, because if u subtract the forces from each other the forward one outweights the other ones

6 0
3 years ago
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