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3 years ago

Please help!!! List three different rock cycles for the following: Sedimentary rock, Metamorphic rock, and Igneous rock.

Chemistry

2 answers:

ValentinkaMS [17]3 years ago

8 0

Sedimentary rocks are formed when different layers of debris ( usually sand ) are forced together under pressure.

Metamorphic rock forms from other types of rock that have been changed by a combination of high heat and pressure.

Igneous rock forms when Lava/Magma cools down

guapka [62]3 years ago

4 0

Igneous- magma cooling
Sedmentary- years of layers of build up

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A weather balloon has a volume of 1750 L at 103 kPa. The balloon is then released to the atmosphere. What is the pressure if at

AnnyKZ [126]

Answer:

35.0 kPa

Explanation:

As pressure decreases, the volume of a gas increases at a given temperature., so since the balloon got bigger, the new pressure must be less than 103kPa

Assuming the temperature does not change, use Boyles Law

P1V1 = P2V2

(103kPa) (1750L) = P2 (5150L)

P2 = (103)(1750) / 5150

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3 years ago

Isabel needs an image to represent the carbon cycle for a presentation in her science class. She has the following diagrams to c

den301095 [7]

Answer:

Its B

Explanation:

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3 years ago

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NaOH + HCl -><br> Fe + HCl ->

vfiekz [6]

Answer:

This is an oxidation-reduction (redox) reaction:

2 HI + 2 e- → 2 H0 (reduction)

Fe0 - 2 e- → FeII (oxidation)

HCl is an oxidizing agent, Fe is a reducing agent.

Reactants:

Names: Iron source: wikidata, accessed: 2019-09-07, Fe source: wikidata, accessed: 2019-09-07, Element 26 source: wikidata, accessed: 2019-09-07... show more

HCl – Chlorane source: wikipedia, accessed: 2019-09-27, Hydrogen chloride source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02

Other names: Hydrochloric acid sourc2 2019-09-27source: NIOSH NPG, accessed: 2019-09-02, M source: wikipedia, accessed: 2019-09-27, Uriatic acid source: wikipedia, accessed: 2019-09-27... show more

Appearance: Colorless, transparent liquid, fumes in air if concentrated source: wikipedia, accessed: 2019-09-27; Colorless gas source: wikipedia, accessed: 2019-09-27; Colourless compressed liquefied gas with pungent odour source: ICSC, accessed: 2019-09-04; Colorless to slightly yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.] source: NIOSH NPG, accessed: 2019-09-02

Products:

FeCl2 – Iron(II) chloride source: : 2019-09-27source: ICSC, accessed: 2019-09-04, Iron dichloride source: wikipedia, accessed: 2019-09-27source: ICSC, accessed: 2019-09-04

Other names: Ferrous chloride source 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Rokühnite source: wikipedia, accessed: 2019-09-27, [FeCl3] source: wikidata, accessed: 2019-09-02, FeCl3 source: wikidata, accessed: 2019-09-02

Appearance: Tan solid (anhydrous) | Pale green solid (di-tetrahydrate) source: wikipedia, accessed: 2019-09-27; White-to-light-green hygroscopic crystals source: ICSC, accessed: 2019-09-04

Names: Dihydrogen source 2019-09-07, Hydrogen source: ICSC, accessed: 2019-09-04source: wikidata, accessed: 2019-09-07, H2 source: wikidata, accessed: 2019-09-07... show more

Appearance: Odourless colourless compressed gas source: ICSC, accessed: 2019-09-04

Hope this helps

5 0

2 years ago

2.1 g of a hydrocarbon fuel is burned in a calorimeter that contains 280 grams of water initially at 25.00◦C. After the combusti

olga2289 [7]

Answer:

$\large \boxed{\text{933 J}}$

Explanation:

There are three heat transfers involved.

heat from combustion of propane + heat gained by water + heat gained by calorimeter = 0

q₁ + q₂ + q₃ = 0

m₁ΔH + m₂C₂ΔT + C_calΔT = 0

Data:

m₁ = 2.1 g

m₂ = 280 g

Ti = 25.00 °C

T_f = 26.55 °C

Ccal = 92.3 J·°C⁻¹

Calculations:

Let's calculate the heats separately.

1. q₁

q₁ = 2.1 g × ΔH = 2.1ΔH g

2. q₂

ΔT = T_f - Ti = 26.55 °C - 25.00 °C = 1.55 °C

q₂ = 280 g × 4.184 J·°C⁻¹ × 1.55 °C = 1816 J

3. q₃

q₃ = 92.3 J·°C⁻¹ × 1.55 °C = 143.1 J

4. ΔH

$\begin{array}{rcl}\text{2.1$\Delta$H g +1816 J +143.1 J} & = & 0\\\text{2.1$\Delta$H g +1959 J} & = & 0\\\text{2.1$\Delta$H g}& = & \text{-1959 J}\\\Delta H & = & \dfrac{\text{-1959 J}}{\text{2.1 g}}\\\\& = & \textbf{-933 J/g}\\\end{array}\\\text{The combustion releases $\large \boxed{\textbf{933 J}}$ per gram of fuel burned.}$

7 0

3 years ago

Plz help me with this question, I am stuck

zhenek [66]

i only know that E is one of them

7 0

3 years ago