1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irakobra [83]
3 years ago
7

Please help!!! List three different rock cycles for the following: Sedimentary rock, Metamorphic rock, and Igneous rock.

Chemistry
2 answers:
ValentinkaMS [17]3 years ago
8 0

Sedimentary rocks are formed when different layers of debris ( usually sand ) are forced together under pressure.

Metamorphic rock forms from other types of rock that have been changed by a combination of high heat and pressure.

Igneous rock forms when Lava/Magma cools down

guapka [62]3 years ago
4 0
Igneous- magma cooling
Sedmentary- years of layers of build up
You might be interested in
Which of these is NOT true about electromagnets?
Alex17521 [72]

Answer:

Permanent = false

Explanation:

All of the other choices are true

4 0
2 years ago
what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

5 0
3 years ago
Polished metals have a metallic luster, which means that?
DochEvi [55]
Metallic luster refers to the way light casts off of a mineral. Polished metals such as gold have a metallic luster, which makes them look bright and shiny, and reflect more light than other minerals. There are also minerals that have metallic luster, but are not shiny or reflect much light, which is called dull metallic luster. 

Metallic luster - bright, shiny
Dull metallic luster - not shiny
7 0
3 years ago
student mixes vinegar and baking soda inside a sealed plastic bag would the reaction be the same if baking soda and vinegar were
pychu [463]
Yes, because nothing has changed. The same ingredients are used and if one reaction happened in a a bag then why wouldn’t it happen in a container?
3 0
3 years ago
\hy carbon used to reduce the oxide of aluminium to get the metal?
irga5000 [103]

___________________________________________________

Carbon is used to reduce the oxide of aluminium to get the metal, in case condensation happens during this process.

___________________________________________________

Hope this helps!

7 0
3 years ago
Other questions:
  • _Fe2O3+ ___C --> __Fe + ___CO2
    11·1 answer
  • Which of the following precautions is important when using a Bunsen burner or Meker burner?a. Set up your work space so that wir
    11·1 answer
  • Identify the element using the Bohr model below.​
    5·1 answer
  • The image compares the arrangement of electrons in two different neutral atoms.
    11·1 answer
  • A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.
    6·2 answers
  • 5. If two gases are present in a contain the total pressure in the container is equal to ​
    11·1 answer
  • Hãy cho biết giá trị và ý nghĩa của số lượng tử n, l, m, ms khi mô tả trạng thái của electron trong nguyên tử?
    7·1 answer
  • What is the value of 100 ºC on the Kelvin scale? A. 100 K B. 273 K C. 373 K D. -373 K E. -300 K
    11·2 answers
  • Plz i wanna those answers click on the photo to see all the question they are 2 queastions part A and B
    10·1 answer
  • Can yall assist me with this lab? It is really screwing me up... No spam!! the only part that I need is the last page. I will ma
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!