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Alexeev081 [22]
3 years ago
15

A spherical helium filled balloon (B) with a hanging passenger cage being held by a single vertical cable (C) attached to Earth

(Cable is going from the cage to ground). If the total mass of the balloon and the cage is 200 kg and the radius of the balloon is 5 m, how much tension (at least), the cable could be able to support in order to keep the balloon from breaking away. (Density of air is approximately 1.225 kg/m3 .)
Physics
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer:

The tension is  T  = 4326.7 \  N

Explanation:

From the question we are told that

   The  total mass is  m  =  200 \  kg

    The  radius is r = 5 \  m

     The  density of air is  \rho_a  =  1.225 \ kg/m^3

Generally the upward  force acting on the balloon is mathematically represented as

        F_N  =   T  + mg

=>     (\rho_a  *  V  *  g ) =   T  + mg

=>   T  =  (\rho_a  * V  *  g   )  - mg

Here V is the volume  of the spherical helium filled balloon which is mathematically represented as

      V  =  \frac{4}{3}  * \pi r^3

=>   V  =  \frac{4}{3}  * 3.142 *(5)^3

=>   V  = 523.67\  m^3

So

    T  = (1.225 *  523.67*  9.8 ) -  200 *  9.8

   T  = 4326.7 \  N

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A 6 N and a 10 N force act on an object. The moment arm of the 6 N force is 0.2 m. If the 10 N force produces five times the tor
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The moment arm is 0.6 m

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\tau_{2}=5 \tau_{1}

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Put the value of torque in the equation

F_{2}\times d_{2}=5\times F_{1}\times r_{1}

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Where, F_{1}=First force

F_{1}=First force

F_{2}=Second force

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Put the value into the formula

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