Answer:
The answer is 312.5j
Explanation:
The kinetic energy (KE):
KE=1/2*m*v^2
M= mass of the object
v= velocity of the object
We have;
m=25g
v=5m/s
KE=1/2*25g*5^2m/s
KE =312.5j
1. this is not physics this is anatomy.
2.circulatory system is the flow of blood through the vena cava, right artrium, right ventricle, pulmonary valve, pulmonary ventricle, left atrium, left ventricle, arteries, capillaries, veins vena cava. digestive system is food through the esophagus, stomach, etc. no direct relation.
Answer:
112 m/s², 79.1°
Explanation:
In the x direction, given:
x₀ = 0 m
x = 19,500 cos 32.0° m
v₀ = 1810 cos 20.0° m/s
t = 9.20 s
Find: a
x = x₀ + v₀ t + ½ at²
19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²
a = 21.01 m/s²
In the y direction, given:
y₀ = 0 m
y = 19,500 sin 32.0° m
v₀ = 1810 sin 20.0° m/s
t = 9.20 s
Find: a
y = y₀ + v₀ t + ½ at²
19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²
a = 109.6 m/s²
The magnitude of the acceleration is:
a² = ax² + ay²
a² = (21.01)² + (109.6)²
a = 112 m/s²
And the direction is:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ = 79.1°
Answer:
a) Tb = m (g + vb² / R)
, b) Tt = m (g - vt² /R), c) Tb = Ty + (vb² -vt²) /R
Explanation:
a) For this exercise we will use Newton's second law, at the bottom
Tb - W = m a
Where the acceleration is centripetal
a = v² / R
Tb = W + m vb² / r
Tb = m (g + vb² / R)
b) the tension at the top
-Tt -w = m a
Tt = W - m vt² / R
Tt = m (g - vt² / R)
c) write the two equations and solve system
Tb = m (g + vb² / R)
Tt = m (g - vt² / R) (-1)
We multiply by (1) and add
Tb -Ty = vb² /R -vt² /R
Tb = Ty + (vb² -vt²) / R