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Goryan [66]
1 year ago
11

Volatile organic solvents have been implicated in adverse health effects in industrial workers. Greener methods are phasing thes

e solvents out. Rank the solvents in Table 13.6 (p. 544) in terms of increasing volatility.
Chemistry
1 answer:
Viktor [21]1 year ago
3 0

Volatile organic solvents consists of variety of chemical gases which are emitted in form of solid or liquids.

Everyday household products also emit these compounds which includes wax, paints which are applied on walls of the house.

These compounds are called as volatile substance because they have higher vapour pressure, and lower boiling points than as compared to the other compounds.

Common emissions sources of VOCs include dry cleaners; auto body shops; cars, trucks, and buses etc.

Volatile organic solvents play a vital role in the creation of ground-level ozone. Ground-level ozone can irritate the eyes, nose, and throat, and can aggravate asthma and other lung diseases, including bronchitis.

To know more about Ozone, refer to this link:

brainly.com/question/14330630

#SPJ4

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Phosgene, COCl2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide w
jek_recluse [69]

The question is incomplete, here is the complete question:

Phosgene, COCl_2, gained notoriety as a chemical weapon in World War I. Phosgene is produced by the reaction of carbon monoxide with chlorine:  

CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

The value of K_c for this reaction is 5.79 at 570 K. What are the equilibrium partial pressures of the three gases if a reaction vessel initially contains a mixture of the reactants in which p_{CO}=p_{Cl_2}=0.265atm and p_{COCl_2}=0.000atm ?

<u>Answer:</u> The equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

<u>Explanation:</u>

The relation of K_c\text{ and }K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p = Equilibrium constant in terms of partial pressure

K_c = Equilibrium constant in terms of concentration = 5.79

\Delta n_g = Difference between gaseous moles on product side and reactant side = n_{g,p}-n_{g,r}=1-2=-1

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

T = Temperature = 570 K

Putting values in above equation, we get:

K_p=5.79\times (0.0821\times 570)^{-1}\\\\K_p=0.124

We are given:

Initial partial pressure of CO = 0.265 atm

Initial partial pressure of chlorine gas = 0.265 atm

Initial partial pressure of phosgene = 0.00 atm

The given chemical equation follows:

                      CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

<u>Initial:</u>            0.265      0.265

<u>At eqllm:</u>        0.265-x    0.265-x        x

The expression of K_p for above equation follows:

K_p=\frac{p_{COCl_2}}{p_{CO}\times p_{Cl_2}}

Putting values in above equation, we get:

0.124=\frac{x}{(0.265-x)\times (0.265-x)}\\\\x=0.0082,8.59

Neglecting the value of x = 8.59 because equilibrium partial pressure cannot be greater than initial pressure

So, the equilibrium partial pressure of CO = (0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of Cl_2=(0.265-x)=(0.265-0.008)=0.257atm

The equilibrium partial pressure of COCl_2=x=0.008atm

Hence, the equilibrium partial pressure of CO, Cl_2\text{ and }COCl_2 is 0.257 atm, 0.257 atm and 0.008 atm respectively.

6 0
3 years ago
What happens when the kinetic energy of particles in a liquid state increases?
Hitman42 [59]

Answer:

When the kinetic energy of particles in liquid increases, the particles are pushed farther apart. This can result in the expansion of matter. More pressure will be exerted on the container in which this liquid is stored.

HOPE THIS ANSWER IS HELPFUL!!

7 0
3 years ago
If the half-life of C-14 is 5730 years, how much C-14 would be left from a 5000 year-old sample that started as 150 grams?
serious [3.7K]
<h3>Answer:</h3>

81.9 grams

<h3>Explanation:</h3>

From the question we are given;

  • Half-life of C-14 is 5730 years
  • Original mass of C-14 (N₀) = 150 grams
  • Time taken, t = 5000 years

We are required to determine the mass left after 5000 years

  • Using the formula;
  • N = No(1/2)^t/T​, where N is the remaining mass, N₀ is the original mass, t is the time taken and T is the half-life.

   t/T = 5000 yrs ÷ 5730 yrs

    = 0.873

N = 150 g ÷ 0.5^0.873

   = 150 g × 0.546

   = 81.9 g

Therefore, the mass of C-14 left after 5000 yrs is 81.9 g

5 0
3 years ago
Describe the two methods to increase the rate at which a substance dissolves.
Liono4ka [1.6K]
Stirring faster, heating up the substance
By stirring faster, more of the solute/solvent come in contact faster.
By heating up a substance, the same things happens.

Hope this helps!
6 0
3 years ago
In _, Solon was chosen as an Athenian statesman with reformation powers.
NeX [460]
594 B.C.E.

In 594 B.C.E., Solon was chosen as an Athenian statesman with reformation powers.
3 0
3 years ago
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