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3 years ago

11

Use this equqation for the problem:4Al+3O2 --> 2Al2O3 How many moles of oxygen are needed to completely react with 14.8 mol o

f Al?

1 answer:

Lesechka [4]3 years ago

7 0

Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion

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When scientists look at these examples, what do they know about the atoms? Carbon-12 Carbon-14

lorasvet [3.4K]

Carbon-12 and Carbon-14 are isotopes of Carbon. Although they have the same number of protons, the <span>number of neutrons in each atom is not the same~</span>

3 0

3 years ago

LOOK AT THE IMAGE ABOVE PLEASE SOMEONE HELP OMG PLEASE IM LITERALLY STRESSED PLEASE HELP. I got the answer wrong. Please help an

Anna35 [415]

D, the more liquid there is, the less the temperature will be affected

8 0

2 years ago

Calculate the number of milliliters of 0.710 M Ba(OH)2 required to precipitate all of the Mn2+ ions in 161 mL of 0.796 M KMnO4 s

USPshnik [31]

<u>Answer:</u> The volume of barium hydroxide is 183 mL.

<u>Explanation:</u>

To calculate the moles of cadmium nitrate, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of $MnSO_4$ = 0.796 M

Volume of $MnSO_4$ = 161 mL = 0.161 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.796mol/L=\frac{\text{Moles of }MnSO_4}{0.161L}\\\\\text{Moles of }MnSO_4=0.13mol$

The chemical equation for the reaction of manganese sulfate and barium hydroxide follows:

$MnSO_4(aq.)+Ba(OH)_2(aq.)\rightarrow Mn(OH)_2(s)+BaSO_4(aq.)$

By Stoichiometry of the reaction:

1 mole of manganese sulfate reacts with 1 mole of barium hydroxide.

So, 0.13 moles of manganese sulfate will react with = $\frac{1}{1}\times 0.13=0.13mol$ of barium hydroxide

Now, calculating the volume of barium hydroxide by using equation 1, we get:

Moles of barium hydroxide = 0.13 moles

Molarity of barium hydroxide = 0.710 M

Putting values in equation 1, we get:

$0.710mol/L=\frac{0.13mol}{\text{Volume of barium hydroxide}}\\\\\text{Volume of barium hydroxide}=0.183L$

Converting this into milliliters, we use the conversion factor:

1 L = 1000 mL

So, $0.183L=0.183\times 1000=183mL$

Hence, the volume of barium hydroxide is 183 mL.

7 0

3 years ago

What period is the atom in?

lys-0071 [83]

It is in period 3
It is in group 17
It is a chlorine atom because it has 17 electrons which means the atomic number is 17

6 0

2 years ago

Which of the following is true about the mass of atoms?

san4es73 [151]

Answer:

i think the answer is C , atom mass increases with temperature

4 0

2 years ago