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stepan [7]
3 years ago
11

Use this equqation for the problem:4Al+3O2 --> 2Al2O3 How many moles of oxygen are needed to completely react with 14.8 mol o

f Al?​
Chemistry
1 answer:
Lesechka [4]3 years ago
7 0

Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion

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2
son4ous [18]

Answer: The molar enthalpy change is 73.04 kJ/mol

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

moles of HCl= molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol

As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.

volume of water = 100.0 ml + 50.0 ml = 150.0 ml

density of water = 1.0 g/ml

mass of water = volume \times density=150.0ml\times 1.0g/ml=150.0g

q=m\times c\times \Delta T

q = heat released

m = mass  = 150.0 g

c = specific heat = 4.184J/g^0C

\Delta T = change in temperature = 4.83^0C

q=150.0\times 4.184\times 4.83

q=3031.3J

Thus 0.0415 mol of HCl produces heat = 3031.3 J

1 mol of HCL produces heat = \frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ

Thus molar enthalpy change is 73.04 kJ/mol

8 0
3 years ago
How do I revise for a science test due tomorrow? I haven’t revised but I have to get a good score. Anyone please help!
Komok [63]

Answer:

in my opinion find some stuff to help u with it test if you are aloud to bring in a revision boom into your test and get a good night sleep if you can and try not to get stressed about it

7 0
2 years ago
Calculate the moles of of Fe that would be needed to form 336 grams of Cl2 (round your answer to 2 decimals)
IrinaVladis [17]

Answer:

6.32 moles of Fe

Explanation:

The given chemical equation is presented as follows;

2Fe + 3Cl₂ → 2FeCl₃

The mass of Cl₂ in the reaction = 336 grams

The molar mass of chlorine gas Cl₂ = 35.435 g/mol

The number of moles, n = Mass/(Molar mass)

The number of moles of Cl₂ in the reaction, n = 336 g/(35.435 g/mol) ≈ 9.842 moles

From the given reaction, 3 moles of Cl₂ react with 2 moles of Fe to produce 2 moles of FeCl₃

By the law of definite proportions, we have that 9.482 moles of Cl₂ will react with approximately 9.482 × 2/3 = 6.32 moles of Fe to produce approximately 6.32 moles of FeCl₃

Therefore, approximately 6.32 moles of Fe will be required to react with 336 grams of Cl₂.

8 0
2 years ago
Formula for "barium oxide"
Harman [31]
The answer is BaO
hope this helpsssss
4 0
3 years ago
20 POINTS!!
Alenkinab [10]

Answer:

1. molarity is = 0.1174

2. molarity is = 9.3

3. molarity is =0.009392

Explanation:

Q#1.

mass of sucrose is 14.07g

molar mass of sucrose is 342 3g/mol

so, 14.07x1/342.3 = 0.0411

now the volume is of water is 0.35

so, 0.0411/0.35 = 0.1174

Q#2.

concentration is 4.5

so, 4.5x1/1000= 0.0045

then, 0.0411/0.0045 = 9.13

Q#3.

M1M1=M2M2

molarity of the same sucrose is 0.1174

so, diluted in 40mL

and the volumetric flask is 500mL

so, 0.1174x40/500= 0.009392

8 0
3 years ago
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