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3 years ago

11

Use this equqation for the problem:4Al+3O2 --> 2Al2O3 How many moles of oxygen are needed to completely react with 14.8 mol o

f Al?

1 answer:

Lesechka [4]3 years ago

7 0

Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion

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How does the position of an element on the periodic table allow you to determine if the element is a metal or non-metal?

malfutka [58]

Answer:

a jagged black line along the right side of the table separates the metals from the nonmetals. The metals are to the left of the line, the nonmetals are to the right of the line, and the elements immediately next to the line are the metalloids.

Explanation:

7 0

3 years ago

Find the density of a substance that has a mass of 75 g and a volume of 35 mL. Don't forget your units!

Andrew [12]

Answer:

The density of a substance that has a mass of 75 g and a volume of 35 mL is 2.14 $\frac{g}{mL}$

Explanation:

Density is a characteristic property of a substance that relates to the amount of mass it has per unit volume. In other words, density is the property that matter, whether solid, liquid or gas, has to compress into a given space (it measures the amount of mass in a given volume of a substance). It is calculated as the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

In this case, you know:

mass= 75 g
volume= 35 mL

Replacing:

$density=\frac{75 g}{35 mL}$

Solving:

$density=2.14\frac{g}{mL}$

<u><em>The density of a substance that has a mass of 75 g and a volume of 35 mL is 2.14 </em></u> $\frac{g}{mL}$ <u><em></em></u>

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3 years ago

Which is a description of objects found in abundance between Mars and<br> Jupiter?

nirvana33 [79]

I am not sure but rocky bodies ranging from large to small in size

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3 years ago

Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3

Goryan [66]

Answer: 4.22 grams of solute is there in 278 ml of 0.038 M $Fe_2(SO_4)_3$

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Now put all the given values in the formula of molality, we get

$0.038M=\frac{n}{0.278L}$

$n=0.0105mol$

mass of $Fe_2(SO_4)_3$ = $moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g$

Thus 4.22 grams of solute is there in 278 ml of 0.038 M $Fe_2(SO_4)_3$

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3 years ago

ANEK [815]

Knowledge of chemistry allows the public to make informed decisions

5 0

3 years ago

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