Answer: There are 
of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg
Explanation:
According to ideal gas equation:
P = pressure of gas = 895 mm Hg= 1.18 atm (760 mm Hg= 1 atm)
V = Volume of gas = 9.55 ml = 0.00955 L (1 L=1000ml)
n = number of moles = ?
R = gas constant =
T =temperature =
Thus there are of gas are in a container with a volume of 9.55 mL at 35 °C and a pressure of 895 mmHg
Answer:
13.8 moles of water produced.
Explanation:
Given data:
Moles of KMnO₄ = 3.45 mol
Moles of water = ?
Solution:
Chemical equation:
16HCl + 2KMnO₄ → 2KCl + 2MnCl₂ + 5Cl₂ + 8H₂O
Moler ratio of water and KMnO₄:
KMnO₄ : H₂O
2 : 8
3.45 : 8/2×3.45 = 13.8 mol
Hence, 3.45 moles of KMnO₄ will produced 13.8 mol of water.
The answer is chemical weathering
Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/mol
The answer is 43 L if I am correct.
They share a common ancestor, but theyre different species
