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3 years ago

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1. List five exothermic reactions that are going on around you. (10 points)

1 answer:

KonstantinChe [14]3 years ago

5 0

Answer :

Exothermic reactions are those reactions in which a system releases its heat energy to surroundings whereas during endothermic reactions a system absorbs heat energy from surroundings.

Explanation :

Five exothermic reactions that are going on around us

a) Making of ice cubes

b) Rusting of iron

c) Nuclear fission reaction

d) Cellular respiration

e) Condensation of water vapor to form rain.

Following are some endothermic reactions;

1) Photosynthesis $6CO_{2}+12H_{2}O\xrightarrow[sunlight]{chlorophyll}C_{6}H_{12}O_{6}+6H_{2}O+6O_{2}$

2) Mixing of water in Ammonium Nitrate $NH_{4}NO_{3}(s)\overset{H_{2}O(l)}{\rightarrow}NH^{_{3}(aq)}+H_{3}O^{+}$

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Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.

serg [7]

Well formation of metallic bond depends on free electrons.smaal sized atoms hold their electrons more firmly as compared to large size atoms ,this z due to distance of outer shell electrons by nucleus..in this way no of free electrons affect strength of metallic bond..smaal sized atoms release less free electrons..

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4 years ago

Read 2 more answers

Standing on top of a building, Bob tosses a baseball straight up with an initial speed of 15 m/s. It takes 4.0 s for the ball to

r-ruslan [8.4K]

Answer:

48.26 m

Explanation:

time to goes up (till stop for a while in the air - maximum height)

vt = vo + a t

0 = 15 + g . t

0 = 15 + (-9.8) . t

9.8t = 15

t = 1.531 s

so the time left to goes down is

4.0 - 1.531 = 2.469 s

height from the top of building can find it by using

vo =√(2gh)

15 = √(2)(9.8).h

15² = 19.6h

h = 225/19.6 = 11.48 m

so the distance of maximum height to the ground is

t = √(2H/g)

2.469 = √(2H/9.8)

2.469² = 2H/9.8

6.096 = 2H/9.8

2H = 6.096 x 9.8 = 59.74 m

so the vertical distance of the building (or the building height's is)

H - h = 59.74 - 11.48 = 48.26 m

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3 years ago

If the work done when a charge of 5.2 × 10-13 coulombs is moved between two points is 4.7 × 10-12 joules, what is the potential

Papessa [141]

9.0, might be to late but someone in the future might need it.

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4 years ago

As the earth rotates, what is the speed of a physics student in Miami, Florida, at latitude 26∘? Ignore the revolution of the ea

ASHA 777 [7]

Answer:

$v =418 m/s$

Explanation:

given,

Radius of earth = 6400 Km

speed of a physics student in Miami, Florida, at latitude 26° = v

time period of rotation = 24 hour = 24 × 3600

= 86400 s

distance = speed × time

$v = \dfrac{distance}{time}$

$v = \dfrac{6400\times cos (26^0)\times 2 \pi }{86400}$

$v =0.41831 Km/s$

$v =418 m/s$

hence, the velocity of the student is equal to $v =418 m/s$

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3 years ago

0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary for

Paladinen [302]

Assuming the accleration applied was constant, we have

$v=v_0+at\implies v_0+20.0\,\dfrac{\mathrm m}{\mathrm s}=v_0+a(0.10\,\mathrm s)$

$\implies20.0\,\dfrac{\mathrm m}{\mathrm s}=a(0.10\,\mathrm s)$

$\implies a=200\,\dfrac{\mathrm m}{\mathrm s^2}$

Then the force applied to the ball is given by

$F=ma=(0.45\,\mathrm{kg})\left(200\,\dfrac{\mathrm m}{\mathrm s^2}\right)$

$\implies F=90\,\dfrac{\mathrm{kg}\,\mathrm m}{\mathrm s^2}=90.\,\mathrm N$

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3 years ago