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3 years ago

Can you please give me the answers ?

Physics

1 answer:

rodikova [14]3 years ago

7 0

Answer:

237

Explanation:

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Which term below describes a measurement of how hard an object pushes against a surface?

Scilla [17]

I hope the answer is D. Pressure

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3 years ago

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You send a beam of light from a material with index of refraction 1.21 into an unknown material. In order to help identify this

White raven [17]

Answer:

refractive index of the unknown material is 1.33.

Explanation:

μ₁ = 1.21

incidence angle (i) = 41.9°

refraction angle (r) = 37.3°

Let us assume μ be the refractive index of the unknown material

according to snell's law of refraction.

μ₁ sin i = μ₂ sin r

1.21 × sin 41.9° = μ × sin 37.3°

μ = 1.33

hence the refractive index of the unknown material comes out top be 1.33

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3 years ago

A truck accelerates from a stop to 27m/sec in 9 minutes. What was the trucks acceleration?

olchik [2.2K]

The acceleration is 3 m/s per minute, or 0.05 m/s per second.

5 0

3 years ago

Give three examples of how gravity is at work in our solar system.

musickatia [10]

Well.....
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3 years ago

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A 460 W heating unit is designed to operate with an applied potential difference of 120 V (a) By what percentage will its heat o

dybincka [34]

Answer:

(a) = -0.16%

(b) = smaller

Explanation:

given

power = 460 W

potential difference = 120 V

(a) what percentage will its heat output drop if the applied potential difference drops to 110 V ?

we know $p = \frac{v^2}{R}$ .....................(i)

we need to find change in power

$\Delta P = \frac{\Delta (V^2)}{R}$

$\Delta P = \frac{2 V \Delta V}{R}$ ..............(ii)

from equations we get

$\frac{\Delta P}{P} = \frac{2 \Delta V}{V}$

$\frac{\Delta P}{P} = 2 \frac{110 -120}{120}$

$\frac{\Delta P}{P} = -2(\frac{10}{120})$

$\frac{\Delta P}{P} = - 0.16 %$

(b)

if we increase temperature resistance will increase and decrease with decrease in temperature and we know power is inversely proportional to resistance so if potential decrease and it would cause drop in power

and due to this increment of heating power resistance will decrease so actual drop in the power would be smaller

7 0

3 years ago