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Sav [38]
3 years ago
11

Newton began his academic career in 1667. For how long was he a working scientist? Was he a very productive scientist?

Physics
1 answer:
rjkz [21]3 years ago
7 0
Newton's 3 laws are...

inertia: things tend to continue to do what they are doing.

Change: to make something change you need a force to change it. the force needed = the mass times its acceleration

<span> Resistance: When you push on something, it pushes back. 

From yahoo answers
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A substance is round in one container and has a volume of one liter. In a much larger container, the substance is rectangular bu
insens350 [35]

Answer:

Liquid

Explanation:

Solids do not change shape, so we know it's not a solid.

Gases take the shape of their container, but they also expand to the volume of the container.  The substance in this problem has the same volume in different size containers, so we know it's not a gas.

The substance must be a liquid.  It takes the shape of its container but has a constant volume.

8 0
4 years ago
the strong nuclear force is one which acts only on the ____________ (A) electrons in the electron cloud (B) attraction between a
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The strong nuclear force is the force that holds nucleons, aka protons and neutrons in the nucleus together, through the boson called the gluon. It also holds quarks together, which constitutes the protons and neutrons.
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4 years ago
Which of these formulas represents 1 atom of sodium (Na) chemically combined with another element?
Andru [333]
The answer is B. because NaCl are just two elements with one atom from each element
3 0
3 years ago
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What is meant by saying that a wave has a low frequency?
OverLord2011 [107]
The answer is B. The wave is very long.
3 0
4 years ago
A shell is shot with an initial velocity v with arrow0 of 18 m/s, at an angle of θ0 = 60° with the horizontal. At the top of the
BARSIC [14]

Answer:

D = 43 m

Explanation:

given,

initial velocity = 18 m/s

angle θ = 60°

total horizontal distance covered by the shell is

R = \dfrac{v_0^2sin 2\theta}{g}

applying conservation of momentum in horizontal direction

m v₀ cos θ = m₁v₁ + m₂ v₂

m v₀ cos θ = 0.5 m v₂

v₂ = 2 v₀ cos θ.

distance covered by the shell from point of explosion

R' = v t

  = (2 v_0 cos \theta) (\dfrac{v_0^2sin \theta}{g})

  =(2 \dfrac{v_0^2cos \theta sin \theta}{g})

  = \dfrac{v_0^2sin 2\theta}{g}

  = R

total distance traveled by the shell is

D = \dfrac{R}{2}+R'

   = 1.5 R

   = 1.5\dfrac{v_0^2sin 2\theta}{g}

D = 1.5\dfrac{18^2sin 2\times 60}{9.81}

   = 42.9 ≅ 43 m

D = 43 m

3 0
3 years ago
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