Question

An applied force of 20 N is used to accelerate an object to the right across a

Answer 1

Answer:

$F_{norm} = 100 N$

$F_{net}=10 N$

$\mu = 0.10$

$m = 10 kg$

$a=1.0 m/s^2$

Explanation:

To determine the normal force, we just need to analyze the situation along the vertical direction.

The box along the vertical direction is in equilibrium, so the equation of the forces is

$F_{norm} - F_{grav} = 0$

which means that

$F_{norm} = F_{grav} = 100 N$

The net force can be determined by looking at the situation along the horizontal direction (since the net force in the vertical direction) is zero. Here we have:

- An applied force of 20 N forward, $F_{app} = 20 N$

- A frictional force of 10 N backward, $F_{frict} = 10 N$

So, the net force is

$F_{net}=F_{app}-F_{frict}=20-10 = +10 N$ in the forward direction

The expression for the frictional force is

$F_{frict} = \mu F_{norm}$

where $\mu$ is the coefficient of friction. Solving for $\mu$,

$\mu = \frac{F_{frict}}{F_{norm}}=\frac{10}{100}=0.10$

The force of gravity is given by

$F_{grav}=mg$

where m is the mass of the object and $g=10 m/s^2$. Solving for m, we find the mass of the object:

$m=\frac{F_{grav}}{g}=\frac{100}{10}=10 kg$

Finally, the acceleration can be found by using Newton's second law

$F_{net} = ma$

where a is the acceleration. Solving for a,

$a=\frac{F_{net}}{m}=\frac{10}{10}=1.0 m/s^2$