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solmaris [256]
3 years ago
14

A penny is dropped from the top of a building 290 m high. Ignoring air resistance, if

Physics
1 answer:
Kryger [21]3 years ago
5 0

Answer:

1. Velocity = 75.39 m/s

2. Air resistance

3. Mass of the coin

Explanation:

1. Given that the height of the building is 290 m. From Newton's third law of motion,

V^{2} = U^{2} + 2gh

where: V is the final velocity of the coin, U is the initial velocity, g is the force of gravity and h is the height.

Since the coin was dropped from a height, its initial velocity is zero. The force of gravity is taken as 9.8 m/s^{2}, so that:

V^{2} = 0 + 2 x 9.8 x 290

   = 5684

V   = \sqrt{5684}

    = 75.3923

The velocity with which the coin hits the ground is 75.39 m/s.

2. Air resistance: During the free fall of the coin, the direction of wind flow could either cause an increase or decrease the value predicted.

ii. Mass of the coin: This can also affect the predicted value.

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Answer:

The horizontal component of her velocity is approximately 1.389 m/s

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