A penny is dropped from the top of a building 290 m high. Ignoring air resistance, if
1 answer:
Answer:
1. Velocity = 75.39 m/s
2. Air resistance
3. Mass of the coin
Explanation:
1. Given that the height of the building is 290 m. From Newton's third law of motion,
=
+ 2gh
where: V is the final velocity of the coin, U is the initial velocity, g is the force of gravity and h is the height.
Since the coin was dropped from a height, its initial velocity is zero. The force of gravity is taken as 9.8 m/, so that:
= 0 + 2 x 9.8 x 290
= 5684
V =
= 75.3923
The velocity with which the coin hits the ground is 75.39 m/s.
2. Air resistance: During the free fall of the coin, the direction of wind flow could either cause an increase or decrease the value predicted.
ii. Mass of the coin: This can also affect the predicted value.
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Answer:
Explanation:
We know that charge on electron
r= 2 nm
We know that force between two charge given
Now by putting the value
We know that mass of electron
The mass of electron
F= m a
a= Acceleration of electron
a= F/m
initial velocity given that zero ,u=0
<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>
Explanation:
The half-life of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.
In this case, we are given the half life of two elements:
beryllium-13:
beryllium-15:
As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?
We can find it out by the following expression:
Where is the amount we want to find:
Finally:
Therefore:
The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.