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viktelen [127]
4 years ago
6

A simple pendulum is swinging back and forth through a small angle, its motion repeating every 1.06 s. How much longer should th

e pendulum be made in order to increase its period by 0.32 s?
Physics
1 answer:
Svetach [21]4 years ago
6 0

Answer:

The pendulum should be made longer by 0.194m in order to increase its period by 0.32s

Explanation:

using the formula T= 2π\sqrt{\frac{L}{g} }

rearranging the equation and making L subject of formula we have;

L=T²g/4π²

lets calculate the length when T=1.06s

g=9.8m/s² , π=3.124

L=\frac{1.06^{2}*9.8 }{4*3.142^{2} }

L=0.279m

the new period after its increased by  0.32s = 1.06+0.32 =1.38s

L_{2}=\frac{1.38^{2}*9.8 }{4 *3.142^{2} }

L_{2}=0.473m

increase in length = 0.473 -0.279

               =0.194m

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Answer:

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3) Atoms of a given element are identical in mass & chemical properties.

4) Atoms of very different elements have different masses & chemical properties.

5) Atoms combine in the ratio of small whole numbers to form compounds.

6) The relative number & kinds of atoms are constant in a given compound.

It's drawback's are :-

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5 0
3 years ago
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Cosmic Microwave Background radiation is one piece of supporting evidence for the Big Band Theory. Are these microwaves at the l
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it is long.

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3 0
3 years ago
Which of the following is a small star that has reached the end of its stellar evolution?
Akimi4 [234]
D.) White Dwarf

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Here, M = mass of the Sun.

Hope this helps!
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3 years ago
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A pump can throw a stream of water up to 29.6m. What is the initial speed of the stream when it leaves a hose nozzle.
zhannawk [14.2K]
Hello
We know that the water's kinetic energy upon leaving will be converted into potential energy as it is projected straight up. The maximum height attained by the water is 29.6m.
We know Kinetic Energy is
1/2 * m * v^2
And Potential energy is
m*g*h
Equating,
(m*v^2)/2 = m*g*h
The mass cancels out from each side, making an object's mass irrelevant when its Kinetic and Potential energies are interchanging.
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7 0
3 years ago
A square coil of wire with 15 turns and an area of 0.40 m2 is placed parallel to a magnetic field of 0.75 T. The coil is flipped
Drupady [299]

Answer:

The magnitude of the average induced emf is 90V

Explanation:

Given;

area of the square coil, A = 0.4 m²

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time of change of magnetic field, t = 0.05 s

The magnitude of the average induced emf is given by;

E = -NAB/t

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E = -90 V

|E| = 90 V

Therefore, the magnitude of the average induced emf is 90V

6 0
3 years ago
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