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aliya0001 [1]
3 years ago
12

7. Which of the following accurately describes the relationship between photosynthesis and cellular respiration? A. Photosynthes

is provides cellular respiration with carbon dioxide and water. B. All living organisms must choose only one of these processes for their entire lives. C. The reactants of photosynthesis are the products of cellular respiration and vice versa. D. Cellular respiration provides photosynthesis with oxygen and sugar.
Physics
1 answer:
Scorpion4ik [409]3 years ago
6 0
I believe its C. The reactants of photosynthesis are the products of cellular respiration and vice versa.
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These interneurons transmit impulses to other neurons and thus form a part of the reflux arc.


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If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w
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In order to place a satellite into orbit, it requires enough fuel to supply the necessary mechanical energy. Into what types of
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When a satellite is revolving into the orbit around a planet then we can say

net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have

F_g = F_c

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3 years ago
Four complete waves pass the duck in one second the frequency of this wave is
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3 0
3 years ago
An electron passes through a point 2.83 cm 2.83 cm from a long straight wire as it moves at 35.5 % 35.5% of the speed of light p
igor_vitrenko [27]

Answer:

The magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

Explanation:

Given:

Distance from the wire to the field point r = 2.83 \times 10^{-2} m

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Current I = 17.7 A

For finding the acceleration,

First find the magnetic field due to wire,

  B = \frac{\mu _{o}I }{2\pi r }

Where \mu_{o} = 4\pi   \times 10^{-7}

  B = \frac{4\pi \times 10^{-7}  \times 17.7 }{2\pi (2.83 \times 10^{-2} ) }

  B = 12.50 \times 10^{-5} T

The magnetic force exerted on the electron passing through straight wire,

  F = qvB  

  F = 1.6 \times 10^{-19} \times 0.355 \times 3 \times 10^{8} \times 12.50 \times 10^{-5}

  F = 21.3 \times 10^{-16} N

From the newton's second law

  F = ma

Where m = mass of electron = 9.1 \times 10^{-31} kg

So acceleration is given by,

   a = \frac{F}{m}

   a = \frac{21.3 \times 10^{-16} }{9.1 \times 10^{-31} }

   a = 2.34 \times 10^{15} \frac{m}{s^{2} }

Therefore, the magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

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