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Zarrin [17]
3 years ago
14

Identify the following example as a physical or chemical change. Moisture in the air forms beads of water on a cold window pane.

physical change chemical change
Chemistry
1 answer:
denis23 [38]3 years ago
6 0

<u>Answer:</u> The given example is a physical change.

<u>Explanation:</u>

A chemical change is defined as the change in which chemical composition of a substance changes and results in the formation of a new substance. These are usually irreversible process.

A physical change is defined as the change in which only the shape and size of the substance changes and no new substance is formed. Only phase change occurs in these processes. These are usually considered as a reversible change.

For the given example: Moisture in the air forms beads of water on a cold window pane.

This is a physical change because water was initially present in the gaseous state (Moisture in the air) and when it is coming in contact with the cold window pane, the gaseous state of water gets converted into a liquid state.

Hence, the given example is a physical change.

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Explanation:

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8 0
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The free energy of formation of nitric oxide, NO, at 1000 K (roughly the temperature in an automobile engine during ignition) is
Assoli18 [71]

<u>Answer:</u> The value of K_p for the chemical equation is 8.341\times 10^{-5}

<u>Explanation:</u>

For the given chemical equation:

N_2(g)+O_2(g)\rightarrow 2NO(g)

To calculate the K_p for given value of Gibbs free energy, we use the relation:

\Delta G=-RT\ln K_p

where,

\Delta G = Gibbs free energy = 78 kJ/mol = 78000 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = temperature = 1000 K

K_p = equilibrium constant in terms of partial pressure = ?

Putting values in above equation, we get:

78000J/mol=-(8.314J/Kmol)\times 1000K\times \ln K_p\\\\Kp=8.341\times 10^{-5}

Hence, the value of K_p for the chemical equation is 8.341\times 10^{-5}

4 0
4 years ago
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