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olganol [36]
3 years ago
11

How would you describe the sequence of reactions in a hydrogen bomb? A) A fission reaction is used to trigger a fusion reaction.

B) A fusion reaction is used to trigger a fission reaction. C) A synthesis reaction is used to trigger a nuclear reaction. Eliminate D) A displacement reaction is used to trigger a decomposition reaction.
Physics
1 answer:
sertanlavr [38]3 years ago
8 0

The Hydrogen bomb is a thermonuclear bomb where a fission reaction is used to trigger a fusion reaction.

Answer: Option A

<u>Explanation: </u>

The Concept of Hydrogen Bomb or H-Bomb is primarily based on nuclear fusion where different isotopes of hydrogen diffuse to fuse their atomic nuclei into a bigger atom, releasing a significant and enormous amount of energy that can ruin a half of the world.

A hydrogen or thermonuclear bomb contains a firearm, but the reaction process has two stages. Uses primary fission energy to activate the next fusion reaction. The energy out by the fusion is nearly four times more than the energy out during fission, which gives more power to a hydrogen bomb.

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The Large Hadron collider (LHC) is a huge piece of equipment designed and built in order to make new scientific discoveries. The
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D

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Easy defimation of newtons second law of motion
shtirl [24]
Hi pupil here's your answer ::

_______________________________

Newton's Second Law  of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force.
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8 0
3 years ago
Two particles, with charges of 20.0 nC and -20.0 nC, are fixed at points with coordinates &lt;0, 4.00 cm&gt; and &lt;0, -4.00 cm
Dmitry [639]

Answer:

Explanation:

Potential energy of the system of charges

=  9 x 10⁹ x [  q₁q₂ / r₁₂ +  q₂q₃ / r₂₃ +  q₁q₃ / r₁₃ ]

here  r₁₂ ,  r₂₃ , r₁₃ are distance between 1 st and 2 nd charge , 2 nd and 3 rd charge and fist and third charge.

r₁₂ = 8 cm , r₂₃ = 4 cm , r₁₃ = 4 cm.

q₁ = 20 x 10⁻⁹ C , q₂ = - 20 x 10⁻⁹ C , q₃ = 10 x 10⁻⁹ C

Potential energy  =  9 x 10⁹ x [ - 400 x 10⁻¹⁸ / .08  +  -200x10⁻¹⁸ / .04 +  200 x 10¹⁸ / .04 ]

= 9 x 10⁹  x  - 400 x 10⁻¹⁸ / .08

= 45 x 10⁻⁶ J .

b)

Potential at the point of fourth charge due to three charges of 20 nC , - 20 nC and 10 nC at the centre

9 x 10⁹ [ 20 x 10⁻⁹ / .05 + - 20 x 10⁻⁹ / .05 + 10 x 10⁻⁹ / .03 ]

= 9 x 10⁹ x 10 x 10⁻⁹ / .03

= 3000 V .

potential energy of fourth particle = charge x potential

= 3000 x 40 x 10⁻⁹ = 12 x 10⁻⁵ J .

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.5 x 2 x 10⁻¹³ x v² = 12 x 10⁻⁵

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v = 3.46 x 10⁴ m/s

= 9 x 10⁹

5 0
3 years ago
Which of these is NOT a possible type of energy transformation?
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