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ycow [4]
3 years ago
11

Identify whether the features and functions belong to the Hubble Space Telescope or the ALMA radio telescope. 1.installed on lan

d. 2.orbits around Earth 3.gets information about stars after they are born 4.gets information about stars before they are born 5.receives light before it enters Earth’s atmosphere 6.receives light after it passes through Earth’s atmosphere
Physics
2 answers:
Ray Of Light [21]3 years ago
7 0

Answer:

<u>Hubble Space Telescope:</u>

2.orbits around Earth

3.gets information about stars after they are born

5.receives light before it enters Earth’s atmosphere

<u>ALMA Radio Telescope: </u>

1.installed on land.

6.receives light after it passes through Earth’s atmosphere

4.gets information about stars before they are born

<u>Explanation:</u>

Hubble space telescope is a space telescope which is placed above Earth's atmosphere. It orbits around Earth and collects data i.e. receives light from the sky before it passes through the atmosphere. Placing it above atmosphere decreases the attenuation of signal.

The ALMA (Atacama Large Millimeter/Submillimeter Array) is an interferometer of 66 radio telescopes installed in the Atacama Desert (Chile). Since, these are installed on land, these telescopes receive light after passing through Earth's atmosphere. The data from these array of telescopes might provide information on birth of star during the early Stelliferous era.

tester [92]3 years ago
5 0
Hublle Space Telescope
- Orbits around  Earth.
- Receive light before it enters Earth's Atmosphere. 
- Get information about stars before they are born.

Alma Radio Telescope
- Installed on land.
- Receive light after it passes through Earth's Atmosphere.
- Get information about stars after they are born. 

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Answer:

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Explanation:

From the question we are told that

    The angle of incidence is  \theta  _ i  = 56^o

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=>       sin \theta_r  =   \frac{sin \theta_i}{n}

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               sin \theta_r__{v}}  =   \frac{sin \theta_i}{n_v}

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                sin \theta_r__{v}}  =   \frac{sin (56)}{2.46}

                 sin \theta_r__{v}}  =  0.337

                 \theta_r__{v}}  =  sin ^{-1} (0.337)

                 \theta_r__{v}}  =  19.69^o

Now considering red light

               sin \theta_r__{R}}  =   \frac{sin \theta_i}{n_r}

substituting values

                sin \theta_r__{R}}  =   \frac{sin (56)}{2.41}

                 sin \theta_r__{R}}  =  0.344

                 \theta_r__{R}}  =  sin ^{-1} (0.344)

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The angle of separation between the red light and the violet light is mathematically evaluated as

                  \Delta \theta = \theta_r__{R}} -  \theta_r__{V}}

substituting values

                  \Delta \theta =20.12 - 19.69

                  \Delta \theta =  0.93 ^o

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