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yaroslaw [1]
3 years ago
10

PLSSS HELP ITS URGENT ILL RATE YOU BRAINLIEST:) A truck whose bed is 4 m long, 2.2 m wide, and 1.0 m high is delivering sand for

a sand-sculpture competition. About how many trips must the truck make to deliver 23 m^3 of sand?
Physics
1 answer:
natka813 [3]3 years ago
8 0

Answer:

one truck load is 2.5*1.5*1 = 3.75m^3

7/3.75 = 1.86 loads,

so 2 trips must be made.

Explanation:

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NEED ANSWER ASAP PLEASE!!!!
gregori [183]
It is boiling point for celsius
8 0
4 years ago
If you have a mineral sample with a volume of 4 ml and a mass of 20 grams , what is the density ?
Vaselesa [24]
Since density would be D=M/V, we’d have to literally divide 20 by 4.
20 divided by 4 is 5, so the density of the mineral sample is 5 grams.
Please correct me if I am wrong!
3 0
3 years ago
Which of the following is true when an object of mass m moving on a horizontal frictionless surface hits and sticks to an object
vivado [14]

Answer:

C. The initial momentum should be equal to the final momentum due to the conservation of momentum.

P_{initial} = mv_0\\P_{final} = (M+m)v_1\\v_1 = \frac{m}{M+m}v_0

Since m/(M+m) < 1, v_1 > v_0.

Explanation:

Wrong -> A. Since the smaller particle still moves after the collision, it has a kinetic energy.

Wrong -> B. The total initial momentum is equal to the momentum of the smaller particle. Therefore, the momentum of the objects that stuck together is equal to that of the smaller object.

Wrong -> D. Since the bigger object is initially at rest and the surface is frictionless, the direction of motion will be the same as the direction of the smaller particle.

4 0
3 years ago
Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hour
Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
4 0
3 years ago
If the same force is exerted on objects with different mass, then the object with less mass have a (smaller or bigger -pick one)
Ratling [72]
Bigger change in velocity because the object is lighter than the object with more mass so it would move further (sorry it’s not a great explanation)
5 0
3 years ago
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