Answer: 3.53 x 10^-4 s
Explanation:
12.7cm x 1m/100cm = 0.127m
V = d/t
t x V = d
t = d/v = 0.127m/(360m/s) = 0.000353s or 3.53 x 10^-4
Answer:


Explanation:
As we know that the force between two small spheres is given as

here we know that
= charges on two small spheres
r = distance between two spheres = 0.15 m
now the force between them is given as


now when two spheres are connected together then the charge on them is equally divided

now the force between them is given as



so here we have


Answer:
Cy and Di
Explanation:
We cannot tell exactly where the right end of the mirror is, but if we assume it is short of allowing Ed and Fred to see each other, we have the following:
Cy can see Cy and everyone to the right
Fred can see Di and everyone to the left
The only two that can see all of Cy, Di, Ed, and Fred are Cy and Di.
_____
If the mirror extends far enough to the right for Ed to see Fred, then all of Cy, Di, and Ed can see the four folks of interest.
Answer:

ω = 0.0347 rad/s²
a ≅ 1.07 m/s²
Explanation:
Given that:
mass of the model airplane = 0.741 kg
radius of the wire = 30.9 m
Force = 0.795 N
The torque produced by the net thrust about the center of the circle can be calculated as:

where;
F represent the magnitude of the thrust
r represent the radius of the wire
Since we have our parameters in set, the next thing to do is to replace it into the above formula;
So;


(b)
Find the angular acceleration of the airplane when it is in level flight rad/s²

where;
I = moment of inertia
ω = angular acceleration
The moment of inertia (I) can also be illustrated as:

I = ( 0.741) × (30.9)²
I = 0.741 × 954.81
I = 707.51 Kg.m²

Making angular acceleration the subject of the formula; we have;

ω = 
ω = 0.0347 rad/s²
(c)
Find the linear acceleration of the airplane tangent to its flight path.m/s²
the linear acceleration (a) can be given as:
a = ωr
a = 0.0347 × 30.9
a = 1.07223 m/s²
a ≅ 1.07 m/s²