1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kenny6666 [7]
3 years ago
5

You testify as an "expert witness" in a case involving an accident in which car A slid into the rear of car B, which was stopped

at a red light along a road headed down a hill. You find that the slope of the hill is θ = 12.0°, that the cars were separated by distance d = 25.0 m when the driver of car A put the car into a slide (it lacked any automatic anti-brake-lock system), and that the speed of car A at the onset of braking was v0 = 18.0 m/s.
(a) With what speed did car A hit car B if the coefficient of kinetic friction was 0.60 (dry road surface)?
____ m/s

(b) What was the speed if the coefficient of kinetic friction was 0.10 (road surface covered with wet leaves)?
____ m/s
Physics
1 answer:
natulia [17]3 years ago
3 0

F=mgsinα –F(fr)=

= mgsinα - μmgcosα

a=F/m =g(sinα – μcosα)

=9.8(sin14-0.57•cos14)= -3.04 m/s²

v²=v₀²+2ad

v=sqrt{ v₀²+2ad} =

=sqrt{18²+2• (-3.04) •25}=13.1 m/

You might be interested in
How long does a bullet take to travel 12.7cm when going 360 m/s
Vinil7 [7]

Answer: 3.53 x 10^-4 s

Explanation:

12.7cm x 1m/100cm = 0.127m

V = d/t

t x V = d

t = d/v = 0.127m/(360m/s) = 0.000353s or 3.53 x 10^-4

8 0
3 years ago
Read 2 more answers
Two small, identical conducting spheres repel each other with a force of 0.045 N when they are 0.15 m apart. After a conducting
Levart [38]

Answer:

q_1 = \pm 1.68 \times 10^{-7} C

q_2 = \pm 6.68 \times 10^{-7} C

Explanation:

As we know that the force between two small spheres is given as

F = \frac{kq_1q_2}{r^2}

here we know that

q_1 , q_2 = charges on two small spheres

r = distance between two spheres = 0.15 m

now the force between them is given as

0.045 = \frac{(9\times 10^9)(q_1q_2)}{0.15^2}

q_1q_2 = 1.125 \times 10^{-13}

now when two spheres are connected together then the charge on them is equally divided

q = \frac{q_1+q_2}{2}

now the force between them is given as

F = \frac{k(\frac{q_1+q_2}{2})^2}{0.15^2}

0.070 = \frac{(9\times 10^9)(\frac{q_1+q_2}{2})^2}{0.15^2}

q_1 + q_2 = 8.37\times 10^{-7}

so here we have

q_1 = \pm 1.68 \times 10^{-7} C

q_2 = \pm 6.68 \times 10^{-7} C

5 0
3 years ago
This diagram shows that Al can see the reflections of Ed and Fred in the mirror. Which two students can both see the reflections
vazorg [7]

Answer:

  Cy and Di

Explanation:

We cannot tell exactly where the right end of the mirror is, but if we assume it is short of allowing Ed and Fred to see each other, we have the following:

  Cy can see Cy and everyone to the right

  Fred can see Di and everyone to the left

The only two that can see all of Cy, Di, Ed, and Fred are Cy and Di.

_____

If the mirror extends far enough to the right for Ed to see Fred, then all of Cy, Di, and Ed can see the four folks of interest.

8 0
4 years ago
Read 2 more answers
A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine
Tju [1.3M]

Answer:

_T}=24.57Nm

ω = 0.0347 rad/s²

a ≅ 1.07 m/s²

Explanation:

Given that:

mass of the model airplane = 0.741 kg

radius of the wire = 30.9 m

Force = 0.795 N

The torque produced by the net thrust about the center of the circle can be calculated as:

_T } = Fr

where;

F represent the magnitude of the thrust

r represent the radius of the wire

Since we have our parameters in set, the next thing to do is to replace it into the above formula;

So;

_T}=(0.795)*(30.9)

_T}=24.57Nm

(b)

Find the angular acceleration of the airplane when it is in level flight rad/s²

_T}=I \omega

where;

I = moment of inertia

ω = angular acceleration

The moment of inertia (I) can also be illustrated as:

I = mr^2

I = ( 0.741) × (30.9)²

I = 0.741 × 954.81

I = 707.51 Kg.m²

_T}=I \omega

Making angular acceleration the subject of the formula; we have;

\omega = \frac{_T}{I}

ω = \frac{24.57}{707.51}

ω = 0.0347 rad/s²

(c)

Find the linear acceleration of the airplane tangent to its flight path.m/s²

the linear acceleration (a) can be given as:

a =  ωr

a = 0.0347 × 30.9

a = 1.07223 m/s²

a ≅ 1.07 m/s²

5 0
3 years ago
Who was the fist man on moon
laila [671]

Answer:

Neil Armstrong

Explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • The natural tendency is for entropy to___ over time.
    6·2 answers
  • A 0.111 kg hockey puck moving at 55 m/s is caught by a 80. kg goalie at rest. with what speed does the goalie slide on the frict
    5·1 answer
  • In nuclear reaction 5 kg of reactants give 2kg of products
    10·1 answer
  • Samantha and Emily are pushing a box of textbooks in the same direction across their classroom. Samantha is applying a force of
    7·1 answer
  • Starting with an initial speed of 6.63 m/s at a height of 0.473 m, a 1.67-kg ball swings downward and strikes a 5.91-kg ball tha
    6·1 answer
  • Volcanic and other such activity at the mid-Atlantic ridge extrudes material to fill the gap between separating tectonic plates
    6·1 answer
  • Does h2 have a coefficient?<br><br> A yes<br> B no
    6·1 answer
  • In a uniform electric field, which statement is correct? A All charged particles experience the same force. B All charged partic
    13·1 answer
  • Discuss the negative consequences of the global dependence on fossil fuels.
    10·1 answer
  • An airplanes speed in still air is 240.0 km/h. If the pilot wishes the resultant motion of the plane to be due north when a 60.0
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!