Which of the following demonstrates a double-replacement reaction?

Chemistry

2 answers:

Korolek [52]2 years ago

8 0

Answer: The correct answer is Option A.

Explanation:

For the given options:

Option A: $Na_3PO_4+MnCl_2\rightarrow Mn_3(PO_4)_2+NaCl$

This reaction is considered as a double displacement reaction because here exchange of ions takes place.

Option B: $CaCO_3\rightarrow CaO+CO_2$

This reaction is considered as a decomposition reaction because here one substance is breaking into two smaller substances.

Option C: $2Mg+O_2\rightarrow 2MgO$

This reaction is considered as a synthesis reaction because here two smaller substances are combining in their elemental state to form a single large substance.

Option D: $2AgNO_3+Cu\rightarrow 2Ag+Cu(NO_3)_2$

This reaction is considered as a single displacement reaction because here more reactive element displaces a less reactive element from its chemical reaction.

Hence, the correct answer is Option A.

Volgvan2 years ago

6 0

A: Na3PO4 + MnCl2 > Mn3(PO4)2 + NaCl

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He molecular formula mass of this compound is 180 amu . what are the subscripts in the actual molecular formula?

mezya [45]

I can't actually answer this one if the empirical formula is not given. Luckily, I've found a similar problem from another website. The problem is shown in the picture attached. It shows that the empirical formula is CH₂O. Let's calculate the molar mass of the empirical formula.

Molar mass of E.F = 12 + 2(1) + 16 = 30 g/mol

Then, let's divide this to the molar mass of the molecular formula.
Molar mass of M.F/Molar mass of E.F = 180/30 = 6

Therefore, let's multiply 6 to each subscript in the empirical formula to determine the actual molecular formula.
Actual molecular formula = C₆H₁₂O₆

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2 years ago

A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o

Solnce55 [7]

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where $\frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}$

We're only talking about molar mass and time (t) here so we'll just concentrate on $\sqrt{\frac{M2}{M1} } = \frac{t2}{t1}$ . Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

$\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}$

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

$(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2$