Which statement describes this reaction?

The electron configurations of some elements are given. Based on the electron configurations, which elements can likely form ion

sergeinik [125]

In the case of Zn, it is likely eligible for one charge, as its 3d is full, it can lose the electrons from the 4s2 level that it does to become Zn2+.

Iron has 6 electrons in the 3d energy level, which signifies that it would give up 6+2 to get to the next stable energy level. It is much convenient for it to give up the 4s2 and then one more out of the 3d6 to produce Fe2+ and Fe3+ respectively.

Sodium has one electron to give away in the 3s energy level, as soon as it gives its one electron, it will look like Ne. In silver, the 4d10 energy level is full, it can only give up the 5s1 electron easily.

In the case of cobalt, the electrons can be taken from the 4s2 energy level and then one more out of the 3d7 energy level, and after that more and more again. Thus, it can go from +5 to -1 charge, due to much more happening in the 3d7 energy level.

Therefore, cobalt can likely form ions with multiple charges.

7 0

3 years ago

What amounts to use in sulfur foods?

coldgirl [10]

Answer:

Allium vegetables. Even if you haven't heard the term “allium” before, you're probably a lot more familiar with these vegetables than you think!

Explanation:

3 0

3 years ago

Read 2 more answers

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

Alecsey [184]

Answer:

The wavelength of the emitted photon will be approximately 655 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question, we need to recall Bohr's formula for the energy of each of the orbitals in the hydrogen atom:

$E_{n} = -\frac{m_{e}e^{4}}{2(4\pi\epsilon_{0})^2\hbar^{2}}\frac{1}{n^2} = E_{1}\frac{1}{n^{2}}$ , where:

[tex]m_{e}[tex] = electron mass

e = electron charge

[tex]\epsilon_{0}[tex] = vacuum permittivity

[tex]\hbar[tex] = Planck's constant over 2pi

n = quantum number

[tex]E_{1}[tex] = hydrogen's ground state = -13.6 eV

Therefore, the energy of the emitted photon is given by the difference of the energy in the 3d orbital minus the energy in the 2nd orbital:

[tex]E_{3} - E_{2} = -13.6 eV(\frac{1}{3^{2}} - \frac{1}{2^{2}})=1.89 eV[tex]

Now, knowing the energy of the photon, we can calculate its wavelength using the equation:

[tex]E = \frac{hc}{\lambda}[tex], where:

E = Photon's energy

h = Planck's constant

c = speed of light in vacuum

[tex]\lambda[tex] = wavelength

Solving for [tex]\lambda[tex] and substituting the required values:

[tex]\lambda = \frac{hc}{E} = \frac{1.239 eV\mu m}{1.89 eV}=0.655\mu m = 655 nm[tex], which correspond to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

5 0

3 years ago

What is the freezing point depression of a solution that contains 0.705?

Sveta_85 [38]

Colligative properties calculations are used for this type of problem. Calculations are as follows:

ΔT(freezing point) = (Kf)m
ΔT(freezing point) = 1.86 °C kg / mol (0.705)
ΔT(freezing point) = 1.3113 °C

Hope this answers the question. Have a nice day.

6 0

3 years ago

PLEASE ANSWER BOTH QUESTIONS I WILL MARK YOU BRAINLIEST IF IT IS CORRECT!!

seropon [69]

Answer:

1st Question: A

2nd Question: B

Explanation:

The 1st answer would be A because if a sample is at absolute zero then the sample is at its lowest temperature none of the molecules would be able to move, this is because lower temperature= lower kinetic energy.

The 2nd answer would be B because if a sample has more temperature it speeds up it has more temperature and more kinetic energy, meaning it would move faster because there is more temperature.

7 0

3 years ago