Answer:
Tension= 21,900N
Components of Normal force
Fnx= 17900N
Fny= 22700N
FN= 28900N
Explanation:
Tension in the cable is calculated by:
Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium
FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)
Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)
Ftorque= 2/3FBcostheta+ 4/3FWcostheta
Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°
Ftorque= 21900N
b) components of Normal force
Efx=FNx-FTcos(90-theta)=0 static equilibrium
Fnx=21900cos(90-55)=17900N
Fy=FNy+ FTsin(90-theta)-FB-FW=0
FNy= -FTsin(90-55)+FB+FW
FNy= -21900sin(35)+(1350+2250)×9.81=22700N
The Normal force
FN=sqrt(17900^2+22700^2)
FN= 28.900N
Answer:
maximum amplitude = 0.08 m
Explanation:
Given that
Time period T= 0.58 s
acceleration of gravity g= 9.8 m/s²
We know that time period of simple harmonic motion given as
T = 2π/ω
0.58 = 2π/ω
ω = 10.83rad/s
ω=angular frequency
Lets take amplitude = A
The maximum acceleration given as
a= ω² A
The maximum acceleration should be equal to g ,then block does not separate
a= ω² A
9.8 = 10.83² A
A = 0.08m
maximum amplitude = 0.08 m
Answer:
A ratio of equivalent units
Explanation:
A conversion factor is a ratio of equivalent units and depends on which units are to be converted.
For example we want to convert 275 [mm] to inches, so we have to find the right conversion factor to allow us to work that conversion.
275 [mm] = inches = ?
![275 [mm] * \frac{1in}{25.4mm} = 10.82 [in]](https://tex.z-dn.net/?f=275%20%5Bmm%5D%20%2A%20%5Cfrac%7B1in%7D%7B25.4mm%7D%20%3D%2010.82%20%5Bin%5D)
In this case the ratio is 1/25.4 = 0.039 [in/mm]
Answer:
True
Explanation:
The smaller object usually moves towards the larger object, because the larger object has more mass than the smaller object, so it has a larger gravitational pull.
