Answer:
They experience the same pressure
Explanation:
To answer this question, we recall Pascal's, Law Pascal's law states that an increase in pressure at a point in a confined cylinder containing a fluid, there is also an equal increase at all other points in that cylinder.
According to Pascal's law the pressure if the pressure expereienced by the larger diameter piston increases, the pressure experienced by the smaller diameter piston also increases by the same amount
However considering that pressure = Force/area F1/A1 =F2/A2
thus where A1 = πD²÷4 and A2 = πD²÷ 16 we have
we have F1×4/πD² = F2×16/πD² or F1 = 4× F2
They experience the same pressure but the larger cylinder delivers four times the force transmitted from he outside to the smaller cylinder
Ionic bond is formed by two opposite type of substances (metal and non-metal) while both covalent or metallic bond is formed by two same type of substances (non-metal and non-metal form covalent bond, metal and metal form metallic bond). Idk if it's true or not.
Explanation:
Can you please make the question more precise..
Thanks..
"n" represents principal energy level or principal quantum number. Principal energy levels are then subdivided into sublevels. The level of principal energy level is always equal to number of sublevels. Therefore if <span>principal energy level</span> = 4, then there are also 4 sublevels present, namely: 4s, 4p, 4d and 4f sublevels.
Answer:
a
b
c
Explanation:
From the question we are told that
The reaction of cyclobutane and oxygen is
ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ
Generally ΔH° for this reaction is mathematically represented as
![\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%20_%7Brxn%7D%20%3D%20%5B%5B4%20%2A%20%5CDelta%20H%5Eo_f%20%28CO_2_%7B%28g%29%7D%20%29%20%2B%204%20%2A%20%5CDelta%20H%5Eo_f%28H_2O_%7B%28g%29%7D%20%5D%20-%5B%5CDelta%20H%5Eo_f%20%28C_2H_6_%7B%28g%29%7D%20%2B%206%20%2A%20%5CDelta%20H%5Eo_f%20%28O_2_%7B%28g%29%7D%29%20%5D%20%5D)
=> ![\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%20_%7Brxn%7D%20%3D%20%5B%5B4%20%2A%20%28-393.5%29%20%2B%204%20%2A%20%28-241.8%29%20%5D%20-%5B%2027.7%20%2B%206%20%2A%200%5D)
=>
Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as
![H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]](https://tex.z-dn.net/?f=H%20%20%3D%20%5B%204%20%2A%20C_%7BCO_2_%7B%28g%29%7D%7D%20%2B%206%2A%20C_%7BCH_2O_%7B%28g%29%7D%7D%5D)
=> ![H = [ 4 * 37.1 + 6* 33.6 ]](https://tex.z-dn.net/?f=H%20%20%3D%20%5B%204%20%2A%2037.1%20%2B%206%2A%2033.6%20%5D)
=>
From the question the initial temperature of reactant is 
Generally the enthalpy change(
) of the reaction is mathematically represented as
=> 
=>
