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3 years ago

What is the difference between transverse and longitudinal waves?

2 answers:

nataly862011 [7]3 years ago

8 0

<span> Displacement of the medium perpendicular to the direction of propagation of the wave. that would be your answer</span>

Deffense [45]3 years ago

3 0

<span>For transverse waves the displacement of the medium is perpendicular to the direction of propagation of the wave. A ripple on a pond and a wave on a string are easily visualized transverse waves. </span>

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A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the magnitude of the dri

nordsb [41]

Complete Question

A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.) mm/s

Answer:

The drift velocity is $v = 0.0002808 \ m/s$

Explanation:

From the question we are told that

The current on the copper is $I = 20 \ A$

The cross-sectional area is $A = 5.261 \ mm^2 = 5.261 *10^{-6} \ m^2$

The number of copper atom in the wire is mathematically evaluated

$n = \frac{\rho * N_a}Z}$

Where $\rho$ is the density of copper with a value $\rho = 8.93 \ g/m^3$

$N_a$ is the Avogadro's number with a value $N_a = 6.02 *10^{23}\ atom/mol$

Z is the molar mass of copper with a value $Z = 63.55 \ g/mol$

$n = \frac{8.93 * 6.02 *10^{23}}{63.55}$

$n = 8.46 * 10^{28} \ atoms /m^3$

Given the 1 atom is equivalent to 1 free electron then the number of free electron is

$N = 8.46 * 10^{28} \ electrons$

The current through the wire is mathematically represented as

$I = N * e * v * A$

substituting values

$20 = 8.46 *10^{28} * (1.60*10^{-19}) * v * 5.261 *10^{-6}$

=> $v = 0.0002808 \ m/s$

8 0

3 years ago

What are the unit for acceleration

Flura [38]

<h3>Answer</h3>

m/s^2 (meter per sec square)

Explanation:

acc = change in velocity/time

= distance/time

----------------

time

= m/s

------

=m/s^2

7 0

3 years ago

Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti

Andreas93 [3]

Answer: 1.88 N

Explanation:

Data:

Force = 4.00N
angle = 62°
horizontal force = ?

Solution:

The trigonometric ratio that relates horizontal - leg to hypotenuse is the cosine.

That ratio is:

                        horizontal - leg
cos(angle) = -------------------------
                          hypotenuse

So, applied to the force, that is:

                             horizontal force
cos (angle) = -----------------------------------
                                 total force

So, clearing the horizontal component you get:

horizontal force = force * cos (angle)

Substitute the data given:

horizontal force = 4.00N * cos(62°) = 4.00N * 0.4695 = 1.88 N

Answer: 1.88N

7 0

3 years ago

Read 2 more answers

Porque un pájaro eriza sus plumas

PolarNik [594]

Answer:

¿Qué estás intentando hoy?

Explanation:

3 0

3 years ago

A row of seats is parallel to a stage at a distance of 90 m from it. At the center and front of the stage is a diffraction horn

Serggg [28]