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3 years ago

10

What is the name of the person that help people at the gym?

2 answers:

tankabanditka [31]3 years ago

7 0

Question: what is the name of the person that help people at the gym?

Answer: a trainer

Explanation: they go around and help people with there exercise and take care of the equipment and tell you how to get in shape

question answered by

(jacemorris04)

frozen [14]3 years ago

5 0

That is called a physical trainer or a fitness coach. Hope I helped!

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The ___________ is the solid Earth, composed principally of rock (by which we mean any naturally formed, nonliving, firm coheren

irina1246 [14]

Answer:

Geosphere

Explanation:

The Geosphere is the solid Earth,composed principally of rock (by which we mean any naturally formed, nonliving, firm coherent aggregate mass of solid matter that constitutes part of a planet).

The geosphere is defined to be that component of the Earth system involving the inside of the Earth, rocks and materials, minerals, land forms and the mechanisms that shape the surface of the Earth. Contrary to Christopher Columbus, the Earth is not in itself a perfect sphere.

6 0

3 years ago

anyanavicka [17]

Answer:

The boat will move in the direction of the force exerted.

Explanation:

To describe the motion of the boat, we shall first obtain the net force acting on the boat. This can be obtained as illustrated below:

From the question given above, the following data were obtained:

Force exerted (Fₑ) = 300 N

Resistive force (Fᵣ) = 250 N

Net force (Fₙ) =?

Fₙ = Fₑ – Fᵣ

Fₙ = 300 – 250

Fₙ = 50 N

Thus, the net force acting on the boat is 50 N in the direction of the force exerted.

Since the net force is in the direction of the force exerted, the boat will move in the direction of the force exerted..!

5 0

3 years ago

How much heat (in kJ) is needed to convert 866 g of ice at −10°C to steam at 126°C? (The specific heats of ice and steam are 2.0

elena-14-01-66 [18.8K]

Answer:

2671.3 kJ

Explanation:

m = 866 g at - 10 degree C converts into steam at 126 degree C.

The following steps are there

(1) ice at - 10 degree C converts into ice at 0 degree C

H1 = m x specific heat of ice x ΔT

H1 = 866 x 2.03 x 10 = 17579.8 J

(ii) ice at 0 degree C converts into water at 0 degree C

H2 = m x Latent heat of fusion = 866 x 334 = 289244 J

(iii) water at 0 degree C converts into water at 100 degree C

H3 = m x specific heat of water x ΔT

ΔH3 = 866 x 4.186 x 100 = 362507.6 J

(iv) water at 100 degree C converts into steam at 100 degree C

H4 = m x Lateant heat of vaporisation

H4 = 866 x 2260 = 1957160 J

(v) seam at 100 degree C converts into steam at 126 degree C

H5 = m x specific heat of steam x ΔT

H5 = 866 x 1.99 x 26 = 44806.84 J

The total heat required is

H = H1 + H2 + H3 + H4 + H5

H = 2671298.24 J = 2671.3 kJ

8 0

2 years ago

One hot day, you find yourself going to the refrigerator for a cold drink. In light of the concept of homeostasis, you're acting

meriva

One hot day, you find yourself going to the refrigerator for a cold drink. In light of the concept of homeostasis, you're acting in terms of the drive-reduction theory.

7 0

3 years ago

Read 2 more answers

A simple pendulum is used to measure gravity using the following theoretical equation,TT=2ππ�LL/gg ,where L is the length of the

Elina [12.6K]

Answer:

g ±Δg = (9.8 ± 0.2) m / s²

Explanation:

For the calculation of the acceleration of gravity they indicate the equation of the simple pendulum to use

T = $2\pi \sqrt{ \frac{L}{g} }$

T² = $4\pi ^2 \frac{L}{g}$ 4pi2 L / g

g = $4\pi ^2 \frac{L}{T^2}$

They indicate the average time of 20 measurements 1,823 s, each with an oscillation

let's calculate the magnitude

g = $4\pi ^2 \frac{0.823}{1.823^2}$ 4 pi2 0.823 / 1.823 2

g = 9.7766 m / s²

now let's look for the uncertainty of gravity, as it was obtained from an equation we can use the following error propagation

for the period

T = t / n

ΔT = $\frac{dT}{dt}$ Δt + $\frac{dT}{dn}$ ΔDn

In general, the number of oscillations is small, so we can assume that there are no errors, in this case the number of oscillations of n = 1, consequently

ΔT = Δt / n

ΔT = Δt

now let's look for the uncertainty of g

Δg = $\frac{dg}{dL}$ ΔL + $\frac{dg}{dT}$ ΔT

Δg = $4\pi ^2 \frac{1}{T2}$ ΔL + 4π²L (-2 T⁻³) ΔT

a more manageable way is with the relative error

$\frac{\Delta g}{g} = \frac{\Delta L }{L} + \frac{1}{2} \frac{\Delta T}{T}$

we substitute

Δg = g ( \frac{\Delta L }{L} + \frac{1}{2} \frac{\Delta T}{T}DL / L + ½ Dt / T)

the error in time give us the stanndard deviation

let's calculate

Δg = 9.7766 ( $\frac{0.001}{0.823} + \frac{1}{2} \ \frac{0.671}{1.823}$ )

Δg = 9.7766 (0.001215 + 0.0184)

Δg = 0.19 m / s²

the absolute uncertainty must be true to a significant figure

Δg = 0.2 m / s2

therefore the correct result is

g ±Δg = (9.8 ± 0.2) m / s²

5 0

2 years ago