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madam [21]
3 years ago
7

The intensity of light from a star varies inversely as the square of the distance. If you lived on a planet ten times farther aw

ay from the sun than the Earth, how would the light intensity of the sun compare with that on Earth?
Physics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

the intensity of the sun on the other planet is a hundredth of that of the intensity of the sun on earth.

That is,

Intensity of sun on the other planet, Iₒ = (intensity of the sun on earth, Iₑ)/100

Explanation:

Let the intensity of light be represented by I

Let the distance of the star be d

I ∝ (1/d²)

I = k/d²

For the earth,

Iₑ = k/dₑ²

k = Iₑdₑ²

For the other planet, let intensity be Iₒ and distance be dₒ

Iₒ = k/dₒ²

But dₒ = 10dₑ

Iₒ = k/(10dₑ)²

Iₒ = k/100dₑ²

But k = Iₑdₑ²

Iₒ = Iₑdₑ²/100dₑ² = Iₑ/100

Iₒ = Iₑ/100

Meaning the intensity of the sun on the other planet is a hundredth of that of the intensity on earth.

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A fighter plane is flying overhead at mach 1.20. What angle does the wave front of the shock wave produced make relative to the
Sever21 [200]

Answer: 56.44°

Explanation:

<u>Given:</u>

  • Let u represent the current speed of the plane, <u>1.2 Mach</u>

<em>Converting to SI Units (m/s):</em>

= (1.2 mach)(340 ms^-1 / 1 Mach)

u  = 408 m/s

  • Speed of sound in air, v = 340 m/s

<u>Find:</u>

  • Angle the wave front of the shock wave relative to the plane's direction of motion, θ

We have, sinθ = speed of sound / speed of object

               sinθ = v / u

                   θ = sin^-1 (v / u)  

                      = sin^-1 (340 / 408)

                   θ = 56.44°

7 0
2 years ago
PLEASE HELP
Anvisha [2.4K]

The speed of the rock at 20 m is 34.3 m/s

Explanation:

We can solve this problem by using the law of conservation of energy: the mechanical energy of the rock, sum of its potential energy + its kinetic energy) must be conserved in absence of air resistance. So we can write:

U_i +K_i = U_f + K_f

where :

U_i is the initial potential energy

K_i is the initial kinetic energy

U_f is the final potential energy

K_f is the final kinetic energy

The equation can also be rewritten as  follows:

mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where:

m = 100 kg is the mass of the rock

g=9.8 m/s^2 is the acceleration of gravity

h_i = 80 is the initial height

u = 0 is the initial speed  (the rock starts at rest)

h_f = 20 m is the final height of the rock

v is the final speed when h = 20 m

And solving for v, we find:

v=\sqrt{2g(h_i-h_f)}=\sqrt{2(9.8)(80-20)}=34.3 m/s

Learn more about kinetic energy and potential energy here:

brainly.com/question/6536722

brainly.com/question/1198647  

brainly.com/question/10770261  

#LearnwithBrainly

5 0
3 years ago
A baseball player hits a 140 g baseball with a force of 2800 N. What is the
Murljashka [212]
B because 2800 divide by 40 is 20
6 0
3 years ago
HELP PLS and HURRY
tangare [24]

Answer:

C - 50,000 * 77 * 3

Explanation:

At the top of the hill the potential energy is E= mgh= (160 kg)(9.81 m s^-2)(30 m)= 47088

hope it helps ,

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5 0
2 years ago
A machine which has an energy loss of 10% will have efficiency of​
larisa [96]

Answer:

90%

Explanation:

if you lose 10% of a 100 you get 90

6 0
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