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madam [21]
3 years ago
7

The intensity of light from a star varies inversely as the square of the distance. If you lived on a planet ten times farther aw

ay from the sun than the Earth, how would the light intensity of the sun compare with that on Earth?
Physics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

the intensity of the sun on the other planet is a hundredth of that of the intensity of the sun on earth.

That is,

Intensity of sun on the other planet, Iₒ = (intensity of the sun on earth, Iₑ)/100

Explanation:

Let the intensity of light be represented by I

Let the distance of the star be d

I ∝ (1/d²)

I = k/d²

For the earth,

Iₑ = k/dₑ²

k = Iₑdₑ²

For the other planet, let intensity be Iₒ and distance be dₒ

Iₒ = k/dₒ²

But dₒ = 10dₑ

Iₒ = k/(10dₑ)²

Iₒ = k/100dₑ²

But k = Iₑdₑ²

Iₒ = Iₑdₑ²/100dₑ² = Iₑ/100

Iₒ = Iₑ/100

Meaning the intensity of the sun on the other planet is a hundredth of that of the intensity on earth.

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puteri [66]

Answer:

Higher percentage of runoff water is absorbed by the vegetation whereas 100 % of water runoff on the roofed area.

Explanation:

Higher percentage of runoff water is absorbed by the vegetation and very little amount of runoff water is received on the end of vegetative cover while on the other hand, 100 percent of precipitation water runoff on the surface of roofed or paved area because no water is absorbed by the roof due to its solid surface. The percentage of runoff depends on the factors such as rainfall intensity, slope, soil water storage capacity, and infiltration rate.

5 0
2 years ago
PLS HELP ASAP :(( You observe a car parked on the side of the road. If the car started to move, Which conclusion could you make?
Nostrana [21]

Answer:

The first option

Explanation:

7 0
2 years ago
Read 2 more answers
Calcula la energía cinética de un coche de 500kg de masa que se mueve a la velocidad de 100 km/h. Pasamos la velocidad a las uni
castortr0y [4]

Responder:

192,900.64 Julios

Explicación:

La energía cinética es la energía que posee un cuerpo en virtud de su movimiento. Sea la masa del cuerpo m, su velocidad v.

Energía cinética = 1/2 mv²

Parámetros dados

masa del coche = 500 kg

velocidad = 100 km / h

La velocidad debe estar en m / s según la unidad internacional estándar. Al convertir;

100 km / h = 100 * 1000/3600 m / s

100 km / h = 27,8 m / s

velocidad del cuerpo = 27,8 m / s

Necesario

Energía cinética del coche = 1/2 * 500 * 27,8²

Energía cinética del automóvil = 1/2 * 500 * 771.6

Energía cinética del automóvil = 1/2 * 385,801.28

Energía cinética del automóvil = 192,900.64 Julios

<em>Por lo tanto, la energía cinética del automóvil es 192,900.64 julios.</em>

5 0
3 years ago
Two hypothetical discoveries in Part A deal with moons that, like Earth's moon, are relatively large compared to their planets.
arlik [135]

Answer:

Unusually large moons form in giant impacts, which are relatively rare events

Explanation:

Solution:

- Finding large moons comparable in size to their planets result from impacts of two astro-bodies. The probability of such an event occurring is very rare.

- Even at the best luck, one moon can be made from the result of giant impact. While the probability of 6 planets having moons of comparable sizes is close to impossible. The transition from an undifferentiated cloud to a star system complete with planets and moons takes about 100 million years.

8 0
3 years ago
an 100kg object traveling at 50m/s collides (perfectly inelastic) with a 50kg object initially at rest. what is the sum of the m
TiliK225 [7]

Answer:

5000 kg.m/s

Explanation:

Before collision, momentum of 100 Kg is given by

p=mv where p is momentum, m is the mass of object and v is the velocity,

therefore, the momentum=100*50=5000 kg.m/s

The momentum of the 50 Kg is zero since it's at rest hence v=o

Total momentum before collision is therefore 5000+0=5000 kg.m/s

7 0
3 years ago
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