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sattari [20]
3 years ago
14

A car changes its velocity from 40.0 m/s to -5.0 m/s in 5.0 seconds what was the car average acceleration

Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answ40x-50 =2334

Explanation:

idk

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In which of these samples do the molecules most likely have the most kinetic energy? (2 points)
Vinvika [58]

D, water vapor. Gaseous state would have more kinetic energy, they are moving faster. If you have to compare the same state, then higher temperature would have the higher kinetic energy. But if you have solid and liquid at the same temperature - then liquid would have more.

4 0
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In a physics experiment, a ball is released from rest, and it falls toward the ground. The timer was not paying attention but es
tigry1 [53]

Answer:

(A) –14m/s

(B) –42.0m

Explanation:

The complete solution can be found in the attachment below.

This involves the knowledge of motion under the action of gravity.

Check below for the full solution to the problem.

4 0
4 years ago
It’s estimated that there are a trillion comets in the Oort cloud, which extends out to about 50,000 AU.How much space does each
dexar [7]

Answer:

  1. Each comet has 523 UA³
  2. The typical spacing would be 8.05 UA
  3. 2.0181x10^21 Joules

Explanation:

  1. Assuming comets are evenly distributed we can find first the volume of a sphere with the formula frac{{4}{3}}πr³ using 50000 as the radius, and then dividing this volume by the amount of comets. This gives a the space each comet has on average.
  2. We apply the cube root as proposed in the question.
  3. The kinectic energy is given <em>K=frac{{1}{2}}mv² where m is the mass and v is the velocity. Apropriate unit are given in the question.</em>

5 0
4 years ago
Is radioactivity on the Earth something relatively new?
luda_lava [24]

naturally occurring radioactive elements have been around since the Earth's formation


3 0
4 years ago
A JFET has a drain current of 5mA. If IDSS = 10mA and VGS ( off )= -6 v. find The Value Of
levacccp [35]

\underline {\huge \boxed{ \sf \color{skyblue}Answer :  }}

<u>Given :</u>

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{D} = 5mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{DSS} = 10mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS(off)} = -6V

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS} =   {?}

\:  \:  \:

<u>Let's Slove :</u><u> </u>

  • \tt \large  I_{D} = I_{(DSS)}  (1 -   \frac {V_{GS}}{V_{GS(off)}} )^{2}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times  V_{GS(off)}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times  { - 6}

\:  \:

  • \underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}
3 0
2 years ago
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