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Alekssandra [29.7K]
3 years ago
14

Materials that are soft and porous will absorb energy causing a decrease in amplitude and energy of the sound. This is called __

______ of the sound.
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0
Damping of the sound
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Why do electrons transfer charge and not protons?
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<h2>Answer:Protons interact in ways that electrons do not. ... Electrons are not affected by the strong force, and so they only get trapped by the electrical attraction to the nucleus which is much weaker in ionized atoms.</h2><h2 /><h2>Explanation:Therefore it is easier for electrons to move away from one atom to another, transferring charge.</h2>

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4 years ago
The client centered approach is emphasized by
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The client-centered approach emphasized the role of the therapist as a facilitator of growth and honored the inherent power of the client.

NOT Emphasis is given to developing a contract for therapy.

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3 years ago
Sail's size and material can make a difference in the effectiveness of how it works because?
Lunna [17]
You need to give more info to your answer so i can help u
7 0
3 years ago
o illustrate the work-energy concept, consider the case of a stone falling from xi to xf under the influence of gravity. Using t
Phantasy [73]

Answer: force of gravity on the body due to height difference above the earth's surface

Explanation: as you increase the height of a body above ground, you do work against gravity in moving it from a point on the earth's surface to that point. So a body falling has a stored up gravito-potential energy which acts on it downward due to its mass, accelerating it downwards

Answer b): kinetic energy of the body

Explanation: the downward force produces an acceleration of magnitude 9.81m/s2 downwards which means an increasing velocity. This increasing velocity means the kinetic energy of the body is increasing (kinetic energy is proportional to velocity of the body squared)

5 0
4 years ago
calculate the density of a neutron star with a radius 1.05 x10^4 m, assuming the mass is distributed uniformly. Treat the neutro
Orlov [11]

To develop this problem it is necessary to apply the concepts related to the proportion of a neutron star referring to the sun and density as a function of mass and volume.

Mathematically it can be expressed as

\rho = \frac{m}{V}

Where

m = Mass (Neutron at this case)

V = Volume

The mass of the neutron star is 1.4times to that of the mass of the sun

The volume of a sphere is determined by the equation

V = \frac{4}{3}\pi R^3

Replacing at the equation we have that

\rho = \frac{1.4m_{sun}}{\frac{4}{3}\pi R^3}

\rho = \frac{1.4(1.989*10^{30})}{\frac{4}{3}\pi (1.05*10^4)^3}

\rho = 5.75*10^{17}kg/m^3

Therefore the density of a neutron star is 5.75*10^{17}kg/m^3

4 0
3 years ago
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