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Llana [10]
3 years ago
13

An airplane is flying at a constant speed in a positive direction. It slows down when it approaches the airport where it's going

to land. Which term describes the slowing of the plane?
1.stationary positive velocity
2.positive acceleration
3.negative acceleration
4.constant velocity
Physics
1 answer:
KatRina [158]3 years ago
5 0
3.negative acceleration....
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A Gaussian surface in the form of a hemisphere of radius R = 5.51 cm lies in a uniform electric field of magnitude E = 1.08 N/C.
Ksju [112]

Answer:

Flux_{base}=-0.0103Nm^2/C

Flux_{curvePortion}=-Flux_{base}=0.0103Nm^2/C

Explanation:

a)At the base of the surface the Electric flux is easy to find, because the Electric Field is constant in magnitude and perpendicular to the flat surface:

Flux_{base}=-E*S=-E*\pi*R^2=-1.08*\pi*0.0551^2=-0.0103Nm^2/C

The Flux is negative because the Electric field goes into the surface

b) The Gaussian surface in form of a hemisphere encloses no net charge. The Gauss law says that the Flux of the electric field is proportional to the net charge enclosed. At this case, the charge is zero, then the total Flux is zero too.

Flux_{total}=Flux_{base}+Flux_{curvePortion}=0

Then:

Flux_{curvePortion}=-Flux_{base}=0.0103Nm^2/C

The Flux is positif because the Electric field goes out of the surface.

4 0
3 years ago
A tuning fork of frequency 254 Hz and an open orang pipe of slightly lower frequency are at 15oC. When
katovenus [111]

The temperature of the air in the open orang pipe has been altered by 18.73° C

The frequency of an open orang pipe is estimated by using the formula:

\mathbf{f = \dfrac{v}{2L}}

Then, the combination of the frequency of the tuning fork and the open orang pipe is:

\mathbf{254 - \dfrac{v}{2L} }

These combinations of frequency produce 4 beats per sound.

i.e.

\mathbf{254 - \dfrac{v}{2L}   =4}

\mathbf{ \dfrac{v}{2L} = 254-4 }

\mathbf{ \dfrac{v}{2L} = 250 ----(1)}

When it is altered, the beats first diminish and increase again by 4.

i.e.

\mathbf{ \dfrac{v'}{2L} = 254+4 }

\mathbf{ \dfrac{v'}{2L} = 258 --- (2) }

If we equate both equations (1) and (2) together, we have:

\mathbf{\dfrac{v'}{v}= \dfrac{258}{250}}

However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.

Hence;

  • when the temperature of the pipe  = unknown ???
  • the temperature of the open orang pipe = 15

∴

\implies \mathbf{\sqrt{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \dfrac{258}{250}}

By squaring both sides, we have:

\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \Big (\dfrac{258}{250}\Big )^2}

\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)= \Big (\dfrac{66564}{62500}\Big )}

\implies \mathbf{\Big(\dfrac{273 + T}{288}\Big)= \Big (1.065024\Big )}

\implies \mathbf{273 +T =306.726912  }

T = 306.726912 - 273

T ≅ 33.73 ° C

∴

The change in temperature ΔT = 33.73° C - 15° C

The change in temperature ΔT = 18.73° C

Learn more about wave frequency here:

brainly.com/question/14316711?referrer=searchResults

4 0
3 years ago
A super ball is dropped from a height of 100 feet. Each time it bounces, it rebounds half the distance it falls. How many feet w
Crank

The total distance travelled by the ball after the fourth impact is 275 feet.

<u>Explanation:</u>

Given-

Height, h = 100 feet

Rebounds half the distance

Distance in feet for the fourth time, x = ?

For the first time, the distance travelled by the ball is, x = 100 feet

For the second time, it will bounce up to 50 feet and fall upto 50 feet( half of 100 feet)

So, the distance travelled after the second impact, x = 100 + 50 + 50 = 200 feet

For the third time, it will bounce up to 25 feet and fall upto 25 feet( half of 50 feet)

So, the distance travelled after the third impact, x = 200 + 25 + 25 = 250 feet

For the fourth time, it will bounce up to 12.5 feet and fall upto 12.5 feet( half of 25 feet)

So, the distance travelled after the fourth impact, x = 250 + 12.5 + 12.5 = 275 feet

Therefore, total distance travelled by the ball after the fourth impact is 275 feet.

4 0
4 years ago
Tanks of compressed gas must be kept away from heat sources. If the temperature of the tank increases too much, it may explode a
yKpoI14uk [10]
"As the gas is heated, the molecules move faster and spread out from each other" is the one among the following choices that <span>best explains why a tank of compressed gas can explode if it is heated. The correct option among all the options that are given in the question is the second option or option "B".</span>
5 0
4 years ago
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An isotope of an element will be radioactive if it has an unstable ratio of____and_____
sammy [17]
Neutrons and protons
5 0
4 years ago
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