Answer:
F = 520 N
Explanation:
For this exercise the rotational equilibrium equation should be used
Σ τ = 0
Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical
Torque is
τ = F x r
the bold indicate vectors, we analyze each force
the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,
The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis
-F z + W x = 0
F z = W x
F =
W
The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator
let's calculate
F = 1300 0.6 / 1.5
F = 520 N
Answer:
convection
Explanation:
The only way convection can only take place in liquids and gas.Since the marshmello is neither,convection is the least effective way
Answer:
It doesn’t really relate
Explanation:
heavier load the parachute must be moving faster to match the downward force of the greater load
and approx terminal velocity when the parachute is open
velocity for Ping pong ball with parachute = 9m/s
velocity for Soccer ball with parachute = 15m/s
velocity for Golf ball with parachute =24m/s
velocity for Watermelon with parachute = 25m/s
so weight of an object doesn’t really realted how fast it falls with a parachute
A eclipse of the sun can only occur at a new moon when the moon passes between earth and sun. If the moons shadow happens to fall upon earths surface at a time, you'll see some portion of the suns disk covered or aka eclipsed by the moon.. I hope that helps
Here is the difference between apparent magnitude and absolute magnitude. When we say apparent magnitude, this is the measurement of the brightness of the star of how it appears on Earth; on the other hand, absolute magnitude is the measurement of the brightness of the star at a <span>standard distance of 32.6 light years, or 10 parsecs. Hope this answers your question.</span>