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Genrish500 [490]
3 years ago
12

The equilibrium constant, Kp = 3.4 for the isomerization reaction:cis-2-butene ⇌ trans-2-butene.If a flask initially contains 0.

25 atm of cis-2-butene what is the equilibrium pressure (atm) for trans-2-butene?
Chemistry
1 answer:
stepladder [879]3 years ago
5 0

Answer:

The equilibrium pressure of trans-2-butene is 0.193 atm.

Explanation:

Kp = Ptrans-2-butene/Pcis-2-butene

Kp = 3.4

Initial pressure of cis-2-butene = 0.25 atm

Let the equilibrium pressure of trans-2-butene be y

From the equation of reaction,

Mole ratio of cis-2-butene to trans-2-butene is 1:1, therefore equilibrium pressure of cis-2-butene is (0.25 - y)

3.4 = y/(0.25 - y)

y = 3.4(0.25 - y)

y = 0.85 - 3.4y

y + 3.4y = 0.85

4.4y = 0.85

y = 0.85/4.4 = 0.193 atm

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<h3>Further explanation</h3>

Given

A ground water tank has its height 2m

Required

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\large{\boxed{\bold {P_h ~ = ~ \rho.g.h}}

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