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3 years ago

What variable did the researchers intentionally vary in the experiment

Physics

1 answer:

Dima020 [189]3 years ago

6 0

Answer: Dependent Variable

Explanation:

There are two types of variable in any kind of experiment:

Independent Variable which are mostly known as inputs

Dependent Variables which are mostly known as outputs

In any experiment, the researches focus on observing the output values (dependent variables) by intentionally changing the inputs (Independent variables).

e.g. If we are observing the strain on any object, we try to change the value of stress on that particular object.

Here strain is a dependent variable whereas stress is an independent variable because it doesn't depend on whatever the value of strain may be.

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Read 2 more answers

A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness

Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

$\sigma_h = \frac{Pd}{2t}$

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

$\sigma_l = \frac{Pd}{4t}$

The letters have the same meaning as before.

Then he hoop stress would be,

$\sigma_h = \frac{Pd}{2t}$

$\sigma_h = \frac{75 \times 8}{2\times 0.25}$

$\sigma_h = 1200psi$

And the longitudinal stress would be

$\sigma_l = \frac{Pd}{4t}$

$\sigma_l = \frac{75\times 8}{4\times 0.25}$

$\sigma_l = 600Psi$

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

$\tau_{max} = \frac{\sigma_h}{2}$

$\tau_{max} = \frac{1200}{2}$

$\tau_{max} = 600Psi$

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

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3 years ago